Answer:
The 99% confidence interval for the proportion of the population who are obese is (0.25, 0.282)
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
For this problem, we have that:
99% confidence level
So , z is the value of Z that has a pvalue of , so .
The lower limit of this interval is:
The upper limit of this interval is:
The 99% confidence interval for the proportion of the population who are obese is (0.25, 0.282)
Answer:
D
Step-by-step explanation:
I might be wrong, so somebody check my answer please. The open circle means that number is not included in the graph. So less than 8 would be D.
Answer:
The answer is B! All I did was take a screenshot of your question and put on my page.
Answer:
125/1000 and no hes not correct
Step-by-step explanation: