To find the slope of the line:
(y2-y1)/(x2-x1)
(14-5)/(4-1)=(9)/(3)=3
Only one of your 4 possible answers has 3 as a slope. However, plugging in each point into the y=mx+b equation, the y-intercept consistently comes out as 2..
y=mx+b
14=3(4)+b b=2
5=3(1)+b b=2
y=3x+2
If there is a consistent, positive slope (from your question, this does not seem to have a quadratic as an option), 3x+5 is not even a viable solution because x=1 when the y-value is 5 (and thus no other x value {0} could have a y-value of 5). It seems as though you have a typo on your hands. Hopefully this helps?
Greatest To Least 1. AC 2. BC 3. AB
11x+3y=103 and y=3x+1.
11x+3(3x+1)=103 -----> plug in (3x+1) for y in the first equation. You will want to distribute the 3 to the 3x+1 to get something that looks like:
11x+9x+3=103 ------> now you want to combine like terms
20x+3=103 ---> subtract 3 from both sides
20x=100 ----> divide both sides by 20
x=5
y=3(5)+1 ---> I like to plug in this to the equation that already has y isolated. 3*5 is 15, add 1 and you find that y=16.
(5, 16) will be your final answer (:
Answer:
(4,3)
Step-by-step explanation:
The solution of two lines is where they intersect
8 pieces = 360°
1 piece = 360 ÷ 8 = 45°
Answer: The last piece measures 45°.
