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2 years ago

13

A car dealership sold 850 cars last year. This year the dealership sold 715 cars. What is the percent decrease, to the nearest p

ercent, in the number of cars sold from last year to this year?????

2 answers:

Bumek [7]2 years ago

3 0

The answer is 16%

Hope this helps :)

Nitella [24]2 years ago

3 0

Answer:

15.8824% decrease

Step-by-step explanation:

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4(2 - d) > - 12 help in any possible

wlad13 [49]

So 4(2-d)>-12, simplify both sides of the inequality -4d + 8> -12, subtract 8 from both sides -4d+8-8>-12-8, -4d> -20, divide both sides by -4 which is -4d÷-4>-20÷-4, then the answer will come out to d<5.

3 0

3 years ago

For a given population of high school seniors, the Scholastic Aptitude Test (SAT) in mathematics has a mean score of 500 with a

tresset_1 [31]

Answer:

The probability that a randomly selected high school senior's score on mathematics part of SAT will be

(a) more than 675 is 0.0401

(b)between 450 and 675 is 0.6514

Step-by-step explanation:

Mean of Sat = $\mu = 500$

Standard deviation = $\sigma = 100$

We will use z score over here

What is the probability that a randomly selected high school senior's score on mathe- matics part of SAT will be

(a) more than 675?

P(X>675)

$Z=\frac{x-\mu}{\sigma}\\Z=\frac{675-500}{100}$

Z=1.75

P(X>675)=1-P(X<675)=1-0.9599=0.0401

b)between 450 and 675?

P(450<X<675)

At x = 675

$Z=\frac{x-\mu}{\sigma}\\Z=\frac{675-500}{100}$

Z=1.75

At x = 450

$Z=\frac{x-\mu}{\sigma}\\Z=\frac{450-500}{100}$

Z=-0.5

P(450<X<675)=0.9599-0.3085=0.6514

Hence the probability that a randomly selected high school senior's score on mathematics part of SAT will be

(a) more than 675 is 0.0401

(b)between 450 and 675 is 0.6514

6 0

3 years ago

A graph is shown below: A graph is shown. The values on the x axis are 0, 2, 4, 6, 8, and 10. The values on the y axis are 0, 4,

pogonyaev

Answer:

<h2>the way its set up its kind of confusing </h2>

Step-by-step explanation:

6 0

3 years ago

How are the graphs of the functions y=2(2)^x and y=2(1.1)^x similar?

Volgvan

If the are equal then they can be similar, otherwise they are not.

4 0

3 years ago

Read 2 more answers

anastassius [24]

Y = -3x - 1......so we sub in -3x - 1 in for y in the other equation

2x + 5y = 12
2x + 5(-3x - 1) = 12....now distribute the 5 through the parenthesis
2x - 15x - 5 = 12...add 5 to both sides
2x - 15x = 12 + 5..combine like terms
-13x = 17...divide both sides by -13
x = -17/13
now sub in -17/13 for x in the other equation
y = -3x - 1
y = -3(-17/13) - 1
y = 51/13 - 1
y = 51/13 - 13/13
y = 38/13

so the solution is (-17/13, 38/13)

8 0

3 years ago