For proof of 3 divisibility, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.
<h3>
Integers divisible by 3</h3>
The proof for divisibility of 3 implies that an integer is divisible by 3 if the sum of the digits is a multiple of 3.
<h3>Proof for the divisibility</h3>
111 = 1 + 1 + 1 = 3 (the sum is multiple of 3 = 3 x 1) (111/3 = 37)
222 = 2 + 2 + 2 = 6 (the sum is multiple of 3 = 3 x 2) (222/3 = 74)
213 = 2 + 1 + 3 = 6 ( (the sum is multiple of 3 = 3 x 2) (213/3 = 71)
27 = 2 + 7 = 9 (the sum is multiple of 3 = 3 x 3) (27/3 = 9)
Thus, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.
Learn more about divisibility here: brainly.com/question/9462805
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It’s equal to 1
2x divide by 2x = 1
— —
2x divide by 2x 1
which equals to 1
Answer:
Step-by-step explanation:
u need to multiply.
Answer:
2x² + 6 = 34x
Step-by-step explanation:
2x² - 10x + 6 = 24x
Collect like terms
2x² + 6 = 24x + 10x
2x² + 6 = 34x
Answer:
The answer would be A
Step-by-step explanation:
When you draw TV with V being the midpoint of SU, you would have two triangles that are congruent on all three sides (SSS). See picture. Hope this helped :)