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Scrat [10]
3 years ago
6

A tree measured 18 1/2 feet tall. Over the next 7 1/2 years, it grew to be 63 1/2 feet tall. During the 7 1/2years, what was the

average yearly growth rate of the tree?
Mathematics
1 answer:
mrs_skeptik [129]3 years ago
5 0

Step-by-step explanation:

first subtract how tall is was 7 1/2 years ago from hell with all it is now. 57 - 40.5 = 16.5 or 16 1/2 so and the seven and a half years the tree Grace 16.5 with 16 1/2 seats to get the average yearly growth for the 7 1/2 year. You have to divide 16 and 1/2 ft by 7 and 1/2 Tim Wiles it makes it much easier if you change the fractions to decimals

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At the popular restaurant Fire Wok, 55%, percent of guests order the signature dish.
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55/100 or 11/20

Since 55% is 55/100 as a fraction. then at it's simplest form it's 11/20.

4 0
3 years ago
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Verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial 4x^3+20x^2+2x-3. Also verify the relationship between the ze
Finger [1]

Solution:

we have been asked to verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial 4x^3+20x^2+2x-3

To verify that whether the given values are zeros or not we will substitute the values in the given Polynomial, if it will returns zero, it mean that value is Zero of the polynomial. But if it return any thing other than zeros it mean that value is not the zero of the polynomial.

Let f(x)=4x^3+20x^2+2x-3\\\\\text{when x=-5}\\\\f(-5)=4(-5)^3+20(-5)^2+2(-5)-3=-13\\\\\text{when x=}\frac{1}{2}\\

f( \frac{1}{2} ) = 4 ( \frac{1}{2} )^3+20(\frac{1}{2})^2+2(\frac{1}{2})-3=\frac{7}{2}\\\\

\text{when x=}\frac{3}{4}\\\\

f( \frac{3}{4} ) = 4 ( \frac{3}{4} )^3+20(\frac{3}{4})^2+2(\frac{3}{4})-3=\frac{183}{16}\\

Hence -5, 1/2, and 3/4 are not the zeroes of the given Polynomial.

Since sum of roots=\frac{-b}{a}= \frac{-20}{4}=-5\\

But -5+\frac{1}{2}+\frac{3}{4}=  \frac{-15}{4}\neq-5

Hence we do not find any relation between the coefficients and zeros.

Anyway if the given values doesn't represents the zeros then those given values will not have any relation with the coefficients of the p[polynomial.

6 0
3 years ago
Factorise x2 + x - 30
Likurg_2 [28]

Answer:

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3 0
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Please help asap<br> find 140% of 82
WITCHER [35]

Answer:

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Step-by-step explanation:

3 0
3 years ago
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Cherie is jogging around a circular track. She
skelet666 [1.2K]

Answer:

Measure of minor angle JOG is 95.5^{\circ}

Step-by-step explanation:

Consider a circular track of radius 120 yards. Assume that Cherie starts from point J and runs 200 yards up to point G.  

\therefore m JG = 200 yards, JO=120 yards.  

Now the measure of minor arc is same as measure of central angle. Therefore minor angle is the central angle \angle JOG = \theta.

To calculate the central angle, use the arc length formula as follows.  

Arc\:Length\left(s\right) = r\:\theta  

Where \theta is measured in radian.

Substituting the value,

200=120\:\theta  

Dividing both side by 120,

\dfrac{200}{120}=\theta  

Reducing the fraction into lowest form by dividing numerator and denominator by 40.

\therefore \dfrac{5}{3}=\theta  

Therefore value of central angle is \angle JOG = \theta=\left(\dfrac{5}{3}\right)^{c}, since angle is in radian

Now convert radian into degree by using following formula,

1^{c}=\left(\dfrac{180}{\pi}\right)^{\circ}

So multiplying \theta with \left(\dfrac{180}{\pi}\right)^{\circ} to convert it into degree.

\left(\dfrac{5}{3}\right)^{c}=\left(\dfrac{5}{3}\right) \times \left(\dfrac{180}{\pi}\right)^{\circ}

Simplifying,

\therefore \theta = 95.49^{circ}

So to nearest tenth, \angle JOG=95.5^{circ}

8 0
4 years ago
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