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Alex
2 years ago
7

Return to the original problem. PEMDAS says to multiply before adding. But could you have performed a different operation and st

ill have gotten a correct answer? Which one? Explain.
(4x2 + 8x + 15) + (x2 − x − 27) − (x + 5)(x − 7)
Mathematics
1 answer:
Brrunno [24]2 years ago
3 0

Answer:

no

Step-by-step explanation:

Because PEMDAS is something you MUST follow no matter WHAT!!!!!!!!

Period pooo

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Ed has 28 blocks. Sue has 34 blocks who has more blocks? How many more?
Anna007 [38]

Answer:

Sue // 6 More blocks

Step-by-step explanation:

Sue has more blocks because 34>28.

34-28 is 6 so sue has 6 more.

3 0
3 years ago
Read 2 more answers
Which of these shapes have the same area?
zvonat [6]

Answer:

wheres the picture?

Step-by-step explanation:

3 0
3 years ago
What is the value of x, when 10(x + 2) = 5(x + 8)?
tatuchka [14]
The value of x is 4. The steps to solving the equation are to use distributive property first so that the equation then looks like this: 10x+20=5x+40
Next you would combine like terms and then the equation would look like this: 5x+20=40
Then you would use the subtraction property of equality to subtract 20 from 40 so your equation will now look like this: 5x=20
Then you use the division property of equality to divide 20 by 5 to get x=4
7 0
3 years ago
Answer answer it it it
lakkis [162]

Answer:

May-June

Step-by-step explanation:

Notice that:

● during April-May period the Badminton memberships rate of increase is greather then Swimming's since the graph of Badminton is showing a faster increase.

● During June-July period, both functions are decreasing so this period does not satisfy our condition.

● During May-June The Swimming memberships growed faster than Badminton's so its rate of increase is greather than Badminton's.

● during August-September period, The swimming memeberships are increasing slower than Badminton's

So the answer is May-June

8 0
3 years ago
Hi Brainly Community!
lana66690 [7]
I think x=6 then the equation would would work
4 0
2 years ago
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