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Lynna [10]
3 years ago
13

The simple interest on a sum of money is 25% of the rate percent per annum find the rate​

Mathematics
1 answer:
kifflom [539]3 years ago
7 0

si =25%*p  

rate =term=t  

from si= ptr/100

term = rate = 5

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I<br> 216<br> Solve the linear equation.<br> 9x - 9 = 5x + 19<br> x=-7<br> x = 7<br> x = 5<br> x = 2
const2013 [10]

Answer:

x=7

Step-by-step explanation:

9x-9=5x+19

Combine like terms

9x-5x=19+9

4x=19+9

4x=28

x=7

5 0
3 years ago
A tire manufacturer warranties its tires to last at least 20,000 miles orâ "you get a new set ofâ tires." In itsâ experience, a
Y_Kistochka [10]

Answer:

Probability that a set of tires wears out before 20,000 miles is 0.1151.

Step-by-step explanation:

We are given that a tire manufacturer warranties its tires to last at least 20,000 miles or "you get a new set of tires." In its past experience, a set of these tires last on average 26,000 miles with S.D. 5,000 miles. Assume that the wear is normally distributed.

<em>Let X = wearing of tires</em>

So, X ~ N(\mu=26,000,\sigma^{2}=5,000^{2})

Now, the z score probability distribution is given by;

         Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = average lasting of tires = 26,000 miles

            \sigma = standard deviation = 5,000 miles

So, probability that a set of tires wears out before 20,000 miles is given by = P(X < 20,000 miles)

    P(X < 20,000) = P( \frac{X-\mu}{\sigma} < \frac{20,000-26,000}{5,000} ) = P(Z < -1.2) = 1 - P(Z \leq 1.2)

                                                                    = 1 - 0.88493 = 0.1151

Therefore, probability that a set of tires wears out before 20,000 miles is 0.1151.

4 0
3 years ago
Round 2.613 to the nearest whole
maxonik [38]

Answer:

that would be 3

Step-by-step explanation:

3 0
4 years ago
Help me please,Thanks
Anna71 [15]
She has 7 more to pack
7 0
3 years ago
Read 2 more answers
How do I solve n x 43.50= 435
Tems11 [23]
How do I solve n x 43.50 = 435 To solve this given expression, there various ways. We can utilize simply by recognizing this as an algebraic equation.
The values then become
1. 43. 50 x n = 435
2. 43.50n = 435
3. N = 435 / 43.50
4. N = 10
Thus, n is 10.



4 0
3 years ago
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