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3 years ago

At Middle school ,60% of the 800 students participate in music. How many students participate in music.???

Mathematics

2 answers:

VikaD [51]3 years ago

5 0

It would be 480, because I did it in Desmos

fredd [130]3 years ago

3 0

Answer:

480

Step-by-step explanation:

800=100% value

x-60%

800/x = 100%/60%

now solve for x

(800/x)*x=(100/60)*x ( multiply both sides of the equation by x )

800=1.66666666667*x ( then we divide both sides of the equation by 1.66666666667 to get x )

480 = x

x= 480

so 60% of 800 is 480

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LenaWriter [7]

Step-by-step explanation:

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6 0

3 years ago

What is the domain of the relation?

amm1812

Domain:

{-4, -2, -1 , 1, 4}

Hope it helps

3 0

4 years ago

Find the distance between the two points rounding to the nearest tenth (if necessary).

leonid [27]

Answer:

$\boxed {\boxed {\sf d\approx 4.2}}$

Step-by-step explanation:

The formula for distance is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

Where (x₁, y) and (x₂, y₂) are the points.

We are given (-6, 6) and (-3, 3). If we match the value and its corresponding variable, we see that:

x₁= -6
y₁ = 6
x₂ = -3
y₂ = 3

Substitute the values into the formula.

$d= \sqrt{ (-3 - -6)^2+(3-6)^2$

Solve inside the parentheses.

-3 --6 = -3+6 = 3
3-6 = -3

$d= \sqrt{(3)^2+ (-3)^2$

Solve the exponents.

(3)²= 3*3= 9
(-3)²= -3*-3 =9

$d= \sqrt{9+9$

Add.

$d= \sqrt18$

$d= 4.24264069$

Round to the nearest tenth. The 4 in the hundredth place tells us to leave the 2 in the tenth place.

$d \approx 4.2$

The distance between the two points is apprximately <u>4.2</u>

4 0

3 years ago

What is the best approximation of the projection of (5,-1) onto (2,6)?

Hatshy [7]

Answer:

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

Step-by-step explanation:

We have given two points $(5, -1)$ and $(2, 6)$ .

Let, $\vec a=5\hat {i}-\hat {j}$ and $\vec b= 2\hat {i}+6\hat{j}$ .

and we have calculate the projection of $\vec a$ onto $\vec b$ .

Now,

For the calculation of projection, first we need to calculate the dot product of $\vec a$ and $\vec b$ .

$\vec a.\vec b=(5\hat {i}-\hat{j}).(2\hat{i}+6\hat{j})$

$=10-6$

$=4$

then, we have to calculate the magnitude of $\vec b$ .

$\mid {\vec {b}}\mid$ = $\sqrt{2^{2}+6^{2} }$ = $\sqrt{40}$ = $2\sqrt{10}$ .

Now, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\vec a.\vec b}{\mid b\mid}$

= $\frac{4}{2\sqrt{10} }$ $\frac{2}{\sqrt{10} } \times\frac{\sqrt{10} }{\sqrt{10} } =\frac{2\sqrt{10} }{10} = \frac{\sqrt{10} }{5}$

and the vector projection of $\vec a$ onto $\vec b$ = $\frac{\vec a. \vec b}{\mid\vec b \mid^{2} } . \vec b$

= $\frac{4}{40} . (2\hat i+ 6\hat j)$

= $\frac{1}{5} \hat i+\frac{3}{5} \hat j$

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

6 0

4 years ago

Savanna had 40 iris blooms last year. This year, she had 15%, percent more iris blooms. How many more iris blooms did Savanna ha

Aleonysh [2.5K]

Answer:

The answer would be 6 irises bloomed last year.

Step-by-step explanation:

let x represent the # of flowers bloomed last year

15% = .15

now just use the equation: quantity = % · whole and plug in the #'s

x = .15 · 40

which equals to x = 6

i hope this helps! :)

7 0

3 years ago