All categories

3 years ago

I need major help pls help

Mathematics

1 answer:

Nesterboy [21]3 years ago

6 0

Answer:

No, since 832 ≠ 900, using Pythagorean theorem, the width should be 18 in

Step-by-step explanation:

It is better to type the question in the 'Question' than the fact that you need help so that we can start seeing the problem immediately.

A rectangle has 4 right angles so if l = 24 and w = 16 then you can use the pythagorean theorem to see if this is possible since

24^2 + 16^2 = 30^2 since the diagonal is the hypotenuse of the triangles formed by the diagonal in the rectangle.

576 + 256 ≠ 900, since the left side is 832 and the right side is 900

It would be more correct if the width is 18 since 576 + 18^2 = 900

You might be interested in

What is (2x-6)(3x-5) equaled to?

Luba_88 [7]

Answer:

6x^2-28x+30

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is the value of b? b/-3=1.5

SVEN [57.7K]

<u> b</u> = 1.5
-3

Cross Multiply

b = - 3 * ( 1.5 )
b = - 4.5

8 0

3 years ago

Read 2 more answers

The Insurance Institute reports that the mean amount of life insurance per household in the US is $110,000. This follows a norma

nata0808 [166]

Answer:

a) $\sigma_{\bar X} = \frac{\sigma}{\sqrt{n}}= \frac{40000}{\sqrt{50}}= 5656.85$

b) Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

c) $P( \bar X >112000) = P(Z>\frac{112000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>0.354)$

And we can use the complement rule and we got:

$P(Z>0.354) = 1-P(Z$

d) $P( \bar X >100000) = P(Z>\frac{100000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>-1.768)$

And we can use the complement rule and we got:

$P(Z>-1.768) = 1-P(Z$

e) $P(100000< \bar X$

And we can use the complement rule and we got:

$P(-1.768$

Step-by-step explanation:

a. If we select a random sample of 50 households, what is the standard error of the mean?

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Let X the random variable that represent the amount of life insurance of a population, and for this case we know the distribution for X is given by:

$X \sim N(110000,40000)$

Where $\mu=110000$ and $\sigma=40000$

If we select a sample size of n =35 the standard error is given by:

$\sigma_{\bar X} = \frac{\sigma}{\sqrt{n}}= \frac{40000}{\sqrt{50}}= 5656.85$

b. What is the expected shape of the distribution of the sample mean?

Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

c. What is the likelihood of selecting a sample with a mean of at least $112,000?

For this case we want this probability:

$P(X > 112000)$

And we can use the z score given by:

$z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$P( \bar X >112000) = P(Z>\frac{112000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>0.354)$

And we can use the complement rule and we got:

$P(Z>0.354) = 1-P(Z$

d. What is the likelihood of selecting a sample with a mean of more than $100,000?

For this case we want this probability:

$P(X > 100000)$

And we can use the z score given by:

$z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$P( \bar X >100000) = P(Z>\frac{100000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>-1.768)$

And we can use the complement rule and we got:

$P(Z>-1.768) = 1-P(Z$

e. Find the likelihood of selecting a sample with a mean of more than $100,000 but less than $112,000

For this case we want this probability:

$P(100000$

And we can use the z score given by:

$z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$P(100000< \bar X$

And we can use the complement rule and we got:

$P(-1.768$

8 0

3 years ago

Can somebody help me? ;)

Korolek [52]

Answer:

No!

Step-by-step explanation:

Hope that helped

4 0

3 years ago

i thought of a number. if i subtract 6 from it and multiply the difference by 4 the result is 36. find the number that i thought

SVEN [57.7K]

Since the difference*4=36, the difference = 9
since the number-6= the difference, the number-6=9
Thus the number is 15

3 0

4 years ago