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2 years ago

5

A candy is in the shape of a sphere. The candy has a radius of 1.5 centimeters. Which of the following is closest to the volume

of the candy? (Use 3.14 for π.)

2 answers:

LenaWriter [7]2 years ago

6 0

Answer:

The answer would be 14 cm

$V = \frac{4pi(1.5)^3}{3}$

$4.5pi = 14.3$

(pi = π)

Your welcome :)

ehidna [41]2 years ago

4 0

Answer:

<u><em>14 cm</em></u>

Step-by-step explanation:

<u><em>THE SIMPLE ANSWER</em></u>

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Rewrite each expression in terms of sine and cosine only.

Sliva [168]

Answer:

1. Cosθ / SineθCosθ

2. Sineθ / Cos²θSineθ

3. Cosθ / Sineθ

4. Cos²θ + Sin²θ – Sin²θ

Step-by-step explanation:

1. SecθCotθ

Recall

Sec θ = 1/Cos θ

Cot θ = 1/Tan θ

But Tan θ = Sine θ / Cos θ

Thus,

Cot θ = 1 ÷ Sine θ / Cos θ

Cot θ = 1 × Cos θ / Sine θ

Cot θ = Cos θ / Sine θ

Therefore,

SecθCotθ = 1/Cos θ × Cos θ / Sine θ

SecθCotθ = Cosθ / SineθCosθ

2. SecθTanθCscθ

Recall

Sec θ = 1/Cos θ

Tan θ = Sine θ / Cos θ

Csc θ = 1/Sine θ

Thus,

SecθTanθCscθ =

1/Cosθ × Sineθ/Cosθ × 1/Sineθ

= Sineθ / Cos²θSineθ

3. Cscθ/Secθ

Recall

Csc θ = 1/Sine θ

Sec θ = 1/Cos θ

Thus,

Cscθ/Secθ = 1/Sine θ ÷ 1/Cos θ

= 1/Sine θ × Cos θ

= Cosθ / Sineθ

4. Cosθ / Secθ

Recall

Sec θ = 1/Cos θ

Cosθ / Secθ = Cosθ ÷ 1/Cosθ

= Cosθ × Cosθ

= Cos²θ

Recall

Cos²θ + Sin²θ = 1

Cos²θ = 1 – Sin²θ

But

1 = Cos²θ + Sin²θ

Thus,

Cos²θ = Cos²θ + Sin²θ – Sin²θ

Therefore,

Cosθ / Secθ = Cos²θ + Sin²θ – Sin²θ

6 0

2 years ago

I NEED HELP WITH THIS I DONT UNDERSTAND IT

nadezda [96]

16.935 I got a question on a test hope this helps):

8 0

3 years ago

What is the true solution to the equation below?

Naddik [55]

Yeeee

assuming your equaiton is
$2ln(e^{ln(2x)})-ln(e^{ln(10x)})=ln(30)$

remember some nice log rules
$log_a(b)=c$ translates to $a^c=b$
and
$a^{log_a(b)}=b$
and
$xlog_c(b)=log_c(b^x)$
and
$ln(x)=log_e(x)$
and
$log(a)-log(b)=log(\frac{a}{b})$
and
if $log(a)=log(b)$ then a=b

so

we can simplify a bit of stuff here

the $e^{ln(2x)} \space\ and \space\ the \space\ e^{ln(10x)}$ can be simplified to $2x \space\ and \space\ 10x$

so we gots now

$2ln(2x)-ln(10x)=ln(30)$
$ln((2x)^2)-ln(10x)=ln(30)$
$ln(4x^2)-ln(10x)=ln(30)$
$ln(\frac{4x^2}{10x})=ln(30)$
same base so
$\frac{4x^2}{10x}=30$
$\frac{2x}{5}=30$
times both sides by 5
$2x=150$
divide both sides by 2
$x=75$
answer is x=75

5 0

3 years ago

lys-0071 [83]

Answer:

$46.2^o$

Step-by-step explanation:

<u><em>The correct question is</em></u>

If b = 9 and c = 13, what is the measure of ∠A? (round to the nearest tenth of a degree)

The picture in the attached figure

we know that

In the right triangle ABC

$cos(A)=\frac{b}{c}$ ---> by CAH (adjacent side divided by the hypotenuse)

substitute the given values

$cos(A)=\frac{9}{13}$

using a calculator

$A=cos^{-1}(\frac{9}{13})=46.2^o$

7 0

3 years ago

The value of the 7 in 507,264 is 10 times the value of the 7 in which number?

monitta

The value of seven is in the thousands place and is 10 time the number seven if it were at the hundreds place, which is where 2 is.

7000=10 x 700
7000=7000

3 0

3 years ago

Read 2 more answers