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Ber [7]
4 years ago
11

Please help! 30 points and crown! A diagonal of a cube measures StartRoot 750 EndRoot cm. The diagonal of a face measures StartR

oot 500 EndRoot cm.
In centimeters, what is the length of an edge of the cube? Round the answer to the nearest tenth.

? centimeters
Mathematics
2 answers:
rodikova [14]4 years ago
8 0

Let length, width, and height be s.

Then diagonal of any face would be √( s² + s² ) = √( 2s² )

And we know that it measures  √( 500 ) so that's sufficient for us to figure out the length of an edge of the cube. We do not need to worry about the diagonal of the cube.

Now we have to solve √( 500 ) = √( 2s² )

Square both sides:

500 = 2s²

Divide both sides by 2:

250 = s²

Take the square root of both sides:

√(250) = s ≈ 15.8113883

Rounding to nearest tenth:

s ≈ 15.8

Final answer: 15.8

Hope this helps.

lutik1710 [3]4 years ago
5 0

Answer:

The person above me is correct

Step-by-step explanation:

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A triangle has sides measuring 7 centimeters and 13 centimeters that form an angle measuring 44°. Which of these is CLOSEST to t
Oliga [24]

Answer:

9.3 centimeters

Step-by-step explanation:

If the length of the third side of the triangle is c, then according to the Law of Cosines, c2 = 72 + 132 – 2(7)(13)(cos 44°). The value of c2 can be simplified to approximately 49 + 169 – 130.9198, or 87.0802, using a calculator. By taking the square root of 87.0802, the length of the third side of the triangle comes out to be approximately 9.3 centimeters.

8 0
3 years ago
The mother's age is 8 times her son's age. After 6 years, the age of the mother will be 9/2 times her son's age. The present age
Sonja [21]

Answer:

s=6 years

m=48 years

Step-by-step explanation:

Let

Mother's age=m

Son's age=s

m=8*s

m=8s (1)

m+6=9/2(s+6)

m+6=9/2s+27 (2)

Substitute (1) into (2)

m+6=9/2(s)+27

8s+6=9/2s+27

8s+6-9/2s-27=0

8s-9/2s-21=0

(16-9/2)s-21=0

7/2s=21

s=21÷7/2

=21×2/7

=42/7

s=6

Present age of the son=6

m=8s

=8(6)

m=48

Present age of the mother=48

5 0
3 years ago
Why are these triangles similar?​
Karo-lina-s [1.5K]
Sides and there angles are similar
6 0
3 years ago
Jason is keeping track of the amount of money that he spends on gas each month. Below are the amounts for last month:
WITCHER [35]
The answer is C. They are all no more than £1.10 off,
5 0
4 years ago
The body temperatures of adults are normally distributed with a mean of 98.6degrees° F and a standard deviation of 0.60degrees°
Schach [20]

Answer:

97.72% probability that their mean body temperature is greater than 98.4degrees° F.

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 98.6, \sigma = 0.6, n = 36, s = \frac{0.6}{\sqrt{36}} = 0.1

If 36 adults are randomly​ selected, find the probability that their mean body temperature is greater than 98.4degrees° F.

This is 1 subtracted by the pvalue of Z when X = 98.4. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{98.4 - 98.6}{0.1}

Z = -2

Z = -2 has a pvalue of 0.0228

1 - 0.0228 = 0.9772

97.72% probability that their mean body temperature is greater than 98.4degrees° F.

6 0
3 years ago
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