The answer to the question is 21/3
Answer:
The probability of the chosen ball being shiny conditional on it being red is; 0.375
Step-by-step explanation:
Let A be the event that a red ball has been chosen
Let B be the event that a shiny ball has been chosen
Let S be the total outcomes = 150 balls
Thus;
P(A ∩ B ) = 36/150
A ∩ B' = 150 - 36 - 54
A ∩ B' = 60
Thus; P(A ∩ B') = 60/150
P(A') = 54/150
P(A) = (150 - 54)/150 = 96/150
Thus, probability of the chosen ball being shiny conditional on it being red is;
P(B | A) = P(B ∩ A)/P(A)
Thus; P(B | A) = (36/150)/(96/150)
P(B | A) = 0.375
The function is L = 10m + 50
Here, we want to find out which of the functions is required to determine the number of lunches L prepared after m minutes
In the question, we already had 50 lunches prepared
We also know that he prepares 10 lunches in one minute
So after A-lunch begins, the number of lunches prepared will be 10 * m = 10m
Adding this to the 50 on ground, then we have the total L lunches
Mathematically, that would be;
L = 10m + 50
