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3 years ago

Plz sove and u will earn 30pts

Mathematics

1 answer:

jeyben [28]3 years ago

6 0

Answer:

Pg. 1:

Triangle A: Obtuse

Triangle B: Obtuse

Triangle C: Acute

Triangle D: Right

Pg. 2:

Question 1: Figure A

Question 2: None

Question 3: Figure C

Pg. 3:

Triangle A: Scalene

Triangle B: Equilateral

Triangle C: Isosceles

Triangle D: Isosceles

Pg. 4:

A: Triangle

B: Circle

C: Rectangle

Hope that helped!

Step-by-step explanation:

You might be interested in

ACB~EFD????????????

photoshop1234 [79]

Answer:

it is similar- this ~ squiggly thing means similar

Step-by-step explanation:

the scale is 3 so x=3.8*3 which is 11.4

hope this helped

7 0

3 years ago

5. A hat contains 13 tickets with numbers 1 to 13 on them. If two tickets are drawn from the hat

Brilliant_brown [7]

Answer:

3.5

Step-by-step explanation:

the original probability is 7/6 favoring odd

4 0

3 years ago

Some parts of California are particularly earthquake-prone. Suppose that in one metropolitan area, of all homeowners are insured

ANTONII [103]

Missing part of the question

Some parts of California are particularly earthquake-prone. Suppose that in one metropolitan area, 25% of all homeowners.....................

Answer:

$P(X = x) = ^4C_x * 0.25^x * 0.75^{4-x}$

$Mean = 1$

$Pr = 0.2617$

Step-by-step explanation:

Given

$n = 4$

$p = 25\%$

Solving (a): The probability distribution of x

We have:

$n = 4$

$p = 25\%$ $= 0.25$

The probability of not having earthquake insurance (q) is:

$q = 1 - p$

$q = 1 - 0.25$ $= 0.75$

If x has insurance, then n - x do not.

The distribution follows a binomial pattern. So, the probability distribution is:

$P(X = x) = ^nC_x * 0.25^x * 0.75^{n-x}$

Substitute 4 for n

$P(X = x) = ^4C_x * 0.25^x * 0.75^{4-x}$

Solving (b): The most likely value of x i.e. The mean

We have:

$n = 4$ and

$p = 25\%$ $= 0.25$

$Mean = np$

$Mean = 4 * 0.25$

$Mean = 1$

Solving (c): At least 2 of 4 selected have earthquake insurance.

This is calculated as

$Pr = P(x = 2) + P(x = 3) + P(x = 4)$

$P(X = x) = ^4C_x * 0.25^x * 0.75^{4-x}$

$P(X=2) = ^4C_2 * 0.25^2 * 0.75^{4-2}$

$P(X=2) = 6 * 0.25^2 * 0.75^2 = 0.2109375$

$P(X=3) = ^4C_3 * 0.25^3 * 0.75^{4-3}$

$P(X=3) = 4 * 0.25^3 * 0.75 = 0.046875$

$P(X=4) = ^4C_4 * 0.25^4 * 0.75^{4-4}$

$P(X=4) = 1 * 0.25^4 * 1= 0.00390625$

So:

$Pr = P(x = 2) + P(x = 3) + P(x = 4)$

$Pr = 0.2109375 + 0.046875 + 0.00390625$

$Pr = 0.26171875$

$Pr = 0.2617$ --- approximated

6 0

3 years ago

Jack and Cameron are playing a game of paper football. By their rules, you can score a 5-point touchdown or a 7-point touchdown.

Inga [223]

X=5 pointn
y=7point
x+y=13
5x+7y=71
solve

multiply first equaiton by -5 and add
-5x-5y=-65
5x+7y=71 +
0x+2y=6

2y=6
divide 2
y=3
sub

x+y=13
x+3=13
x=10

10 five point touchdowns
3 seven point touchdowns

8 0

3 years ago

What is the next number in the sequence 2 7 8 3 12 9

Illusion [34]

2 7 8 3 12 9... 14. the next number would be 14

8 0

3 years ago