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2 years ago

Whats 3.8412 in place values

1 answer:

5 0

3 in the hundred-thousand place, 8 in thousands place, 4 in the hundreds place, 1 in the tens place, 2 in the one's place.

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a baker has 50 pounds of flour. she uses 12 pounds of flour to make bread . what percent of flour does she use????????¿

Daniel [21]

24%. Because 12 divided by 50 times 100 is 24.

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2 years ago

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(11x + 8) + (8x + 12) =27

Tju [1.3M]

Answer:

11x + 8 +8x +12 =27 (drop the parenthesis, there's no actual need for them)

19x +20 =27 (i combined like terms and then subtracted 20 from both sides)

19x = 7 (divide both sides by 19 to get x alone)

x= 7/19 or 0.36842105 (the answer)

Step-by-step explanation:

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2 years ago

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One snake caught 121212 mice.

Nata [24]

120657Step-by-step explanation:

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2 years ago

Find the common difference of the sequence shown 1/6,1/3,1/2,2/3,......

tekilochka [14]

Answer:

Common Difference(d) is

$d=\frac{1}{6}$

Step-by-step explanation:

Given sequence is :

$\frac{1}{6}, \frac{1}{3} ,\frac{1}{2} ,\frac{2}{3} .........$

If a sequence has a constant common difference throughout the sequence, then the sequence is called Arithmetic Progression.

Considering a sequence:

$a_1,a_2,a_3,a_4..........\\$

$a_2-a_1=a_3-a_2=a_4-a_3=a_n-a_n_-_1=d$

where 'd' is the common difference of the A.P.

Similarly, finding the common difference of the given sequence.

$\frac{1}{3} -\frac{1}{6}= \frac{1}{2}- \frac{1}{3}=\frac{2}{3} - \frac{1}{2}=d\\$

$d=\frac{1}{3}-\frac{1}{6}=\frac{(2)(1)-(1)(1)}{6}=\frac{1}{6}$

$d=\frac{1}{6}$

Common Difference(d) is

$d=\frac{1}{6}$

8 0

3 years ago

Read 2 more answers

A single die is rolled twice. the 36 equally-likely outcomes are shown to the right. find the probability of getting two numbers

elena-s [515]

Answer:

1/6

Step-by-step explanation:

When a die is rolled twice the possible outcomes are:

Here the first value represents the first outcome and the second value represents the second outcome.

S = { (1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3),(2,4), (2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6), ( 4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6, 1), (6, 2), (6,3), (6,4), (6,5), (6,6)}

Total outcomes = n(S) = 36

Let A be the event that the sum of both outcomes is 7.

A = {(1, 6) , (2,5), (3,4) , (4,3), (5,2), (6,1)}

n(A) = 6

So, P(A) = n(A)/n(S)

= 6/36

= 1/6

6 0

3 years ago