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babymother [125]
3 years ago
10

Use the Lander and Waterman application of the Poisson distribution to calculate the number of reads that you need to sequence t

o obtain 20X coverage for a genome of size 5 Mb and Illumina reads of 100 bp. How does that compare with the number of reads that you would need with Sanger capillary sequencing (read length 800 bp)
Biology
1 answer:
miskamm [114]3 years ago
3 0

Answer:

120X reads

Explanation:

Data:

The number of the calculated gap of .2% is refered to the genome size in the question. For instance, if we want to sequence 4Mb, the total number of readings will be 800 000. Thus, for a total information, there will be 80 000 000 bp (80 Mbp) which will be 20 times the coverage of the genomes. In fact, there is an insignificant change in the distribution of the genome depending on the size of the reads. Thus, the total information. What is likely to be affected is the general assembly of the genome. A maximum of 25 X on average will yield the about 250 bp. However, for 100 bp, there might be a need of more than 120 X.

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PLEASE HELP ME. ASAP. I can't find anything else online.
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The puppies heads are often to big to fit through their mothers birth canal. They may get birth defects like flat chests, if their face are wrinkly they get acne and eye problems, and they are prone to skeletal disorders like hip dysplasia.
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10. Lichens are among the first organisms to
lara [203]

Answer:

The correct option is H) these acids change the environment.

Explanation:

Soil can be described as the part of the environment where plants grow. In primary succession, life stars arising in an area which has no soil and only rocks, This is possible because lichens are the organisms which can grow on the rocks. Lichens secrete certain acids which break down these rocks and hence soil begins to form when these rocks break. This makes it possible for other plant species to grow on these lands.

8 0
3 years ago
genetics book g how do you know that only a single gene is responsible for he color diferences between these snakes?
mariarad [96]

Answer:

Here is the full question:

An albino corn snake is crossed with a normal colored corn snake. The offspring are all normal-colored. When the first generation progeny snakes are crossed among themselves, they produce 32 normal colored snakes and 10 albino snakes.

a. How do you know that only a single gene is responsible for the color differences between these snakes?

b. which of these phenotypes is controlled by the dominant allele?

c. a normal colored female snake is involved in a test cross. This cross produces 10 normal colored and 11 albina offspring. what are the genotypes of the parents?

Explanation:

First of all, in genetics, Phenotype are the observable physical properties of an organism; these include the organism's appearance, development, and behavior. An organism's phenotype can be determined by its genotype, which is the set of genes the organism carries, as well as by environmental influences on these genes.

Allele, which can also be called allelomorph, is any one of two or more genes that may occur alternatively at a given site on a chromosome. Alleles may occur in pairs, or we may have multiple alleles affecting the phenotype of a particular trait. The combination of alleles that an organism carries is its genotype. If the paired alleles are the same, the organism’s genotype is said to be homozygous for that trait. If they are different, the organism’s genotype is heterozygous. A dominant allele (A) will override the traits of a recessive allele (a) in a heterozygous pairing.

(a) In the question, we have two phenotypes seen in the second generation of this cross: normal and albino. Therefore, only one gene with two alleles is needed to control the phenotypes like colour of the snakes observed. The 3:1 ratio of these phenotypes in the F2 generation will be seen only if a single gene is involved.

(b) The allele controlling the normal phenotype (A) is dominant to the allele controlling the albino phenotype (a).

(c) The male parent’s genotype is aa. The normally colored offspring must receive an A allele from the mother, so the genotype of the normal offspring of the testcross is Aa. The albino offspring must receive an a allele from the mother, so the genotype of the albino offspring of the testcross is aa. Thus, the female parent must be heterozygous Aa.

7 0
3 years ago
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Dimas [21]

Answer:

a d*ck and a yk what-

Explanation:

no need for me to say more,

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