Please help me..........only 32,and 33
1 answer:
Answer:
Step-by-step explanation:
32
Step 1 : Draw PQ = 6cm
Step 2 : Construct 60 degree at Q. [Given PQR = 60=> Q = 60 ]
Step 3 : Take 5 cm on compass and mark 5cm on the 60 degree
line constructed at Q.
Step 4 : The arc of 5cm and 60 degree line meets is the point R.
[Given QR = 5cm ]
Step 5 : Given PQ || SR so construct a 120° at R ,
because ∠PQR and ∠QRS are supplementary angle.
[ ∠PQR + ∠QRS = 60 + 120 = 180° ]
Step 6 : At P , take 6.5 cm on compass and mark on the line drawn in
Step 5, to get S. [ Given PS = 6.5 ]
33
Given adjacent sides : 4.8 and 4.2
And it is a rectangle.
Step 1 : construct AB = 4.8 cm
Step 2 :At A and B construct 90 degree
Step 3: On the compass take 4.2cm and mark on the 90degree lines
from A and B.
Step 4 : Mark that as C and D respectively.
Step 5 : Join CD
You might be interested in
Answer:
781250
Step-by-step explanation:
Let y is the length of the farm field
Let x is the width of the farm field
Given that, no fencing is necessary along the rock wall, so we can find the perimeter of the farm is:
2x + y = 2500 feet
<=> y = 2500 -2x
The are of the farm has the following formula:
A = x*y
<=> A = x(2500 - 2x)
<=> A = 2500x -2
To have the maximum area of field in square feet, we need to use differentials to estimate:
= 2500 - 4x
Set = 0, we have:
2500 - 4x = 0
<=> x = 625 feet.
=> y = 2500 - 2*625 = 1250 feet
So the maximum area of field is:
A = x*y = 625*1250 = 781250
In ∆ABD
In ∆BCD
Now
IN PARALLELOGRAM ABCD
Option A