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andrew11 [14]
3 years ago
9

Lina wanted to buy a bag. She saw a red bag on sale at 15% discount and a blue bag at 20% discount. Both bags had the same origi

nal price before the discounts. To buy the red bag, Lina would need $2.50 more than what she had. So Lina bought the blue bag. After that, she had $2 left. (a) What was the original price of the red bag? (b) How much money did Lina have at first?
Mathematics
1 answer:
Kitty [74]3 years ago
7 0

Answer:

a) The original price of the bag was $90

b) Lina was having $74

Step-by-step explanation:

Let the original price of  the bags be 'x'

and,

the money Lina had be 'y'

then according to the question

Price of red bag after 15% discount = x - 0.15x = 0.85x

Price of red bag after 20% discount = x - 0.20x = 0.80x

also,

0.85x = y + $2.5 ...........(1)

0.80x = y - $2  .............(2)

subtracting the equation (2) from  (1), we get

    0.85x = y + $2.5

- ( 0.80x = y - $2   )

===================

      0.05x = $4.5

or

x = $90

a) The original price of the bag was $90

b) on substituting the value of x in the equation (1), we get

0.85 × 90 = y + $2.5

or

76.5 = y + $2.5

or

y = $74

Hence, Lina was having $74

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tankabanditka [31]

Answer:

The answer to your question is: AC = 20

Step-by-step explanation:

Data

   AB = 2x - 4

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            AB + BC = AC

        2x - 4 + 4x = 2x + 12

       6x - 4 = 2x + 12

       6x - 2x = 12 + 4

       4x = 16

       x = 16/4

       x = 4

AB = 2(4) - 4 = 8 - 4 = 4

BC = 4(4) = 16

AC = 2(4) + 12 = 8 + 12 = 20

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         20 = 20

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3 years ago
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I need help figuring out the answers for this
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<h2>Step-by-step explanation:</h2>

Interest, is an additional money paid for borrowing money. it could be simple or compound interest.

simple interest= p×T×R/100

when interest is compounded annually

F= p(1+r)^t

F= future value

p= principal

r= rate

t= time

compound interest is calculated based on the initial and accumulated interest.

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F= p(n+r)^n

F= 10000(1+0.02)^1

F= 10000×1.02= $10200

interest= 10200-10000

interest = $200

second year

F = 10200(1+0.02)^1

F=10200×1.02= $10404

Interest= 10404-10200

interest= $204

third year

F= 10404(1+0.02)^1

F= 10404(1.02)

F = $10612.08

interest= 10612.08-10404

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<h2>Bob's interest</h2><h2>I= p×t×R/100</h2>

first year

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I= 10000×2×0.02/100

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for the third year

I =10000×3 × 0.02/100

interest= $6

<h2>check answer above for final computation</h2>

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2 years ago
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