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pochemuha
2 years ago
5

Rachel’s earrings are in the shape of a triangle. The height of the earrings is 1 1/2 inches and the base is 3/5 inches. What is

the area of both of Rachel’s earrings?
Formula: A=1/2bh

Formula: A=0.5 x b x h
Mathematics
1 answer:
poizon [28]2 years ago
5 0

Answer:

9/10

Step-by-step explanation:

First, 1 1/2 as a improper fraction is 3/2

Second, 3/2 x 3/5 = 9/10

Third, you need to do 9/10 x 2 since there are two earings which equals 18/10.

Fourth, 18/10 divided by 2 = 9/10 which means that the area of both earrings is 9/10

Hope this helps!

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Kayla is 13 years old. her uncle says that his age minus 22 is equal to kaylas age how old is kaylas uncle?
solniwko [45]
The age of uncle as compared to kavya is 35


4 0
3 years ago
Translate (5, 1) to the right 3 units.
Sergio [31]

Answer:

Step-by-step explanation:

Answer

When you translate either left or right, the x coordinate is the one that you change. To go right when you are dealing with a point, you must add the amount you are asked to go right.  So when you go right 3 units, add 3 to the 5.

(5 + 3,1) = (8,1)

when going across the y axis, you are still only changing the x coordinate.

All you need do is put a minus sign in front of the  x coordinate. So your final answer is (-8,1)

5 0
1 year ago
Differentiate with respect to X <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%5Cfrac%7Bcos2x%7D%7B1%20%2Bsin2x%20%7D%20
Mice21 [21]

Power and chain rule (where the power rule kicks in because \sqrt x=x^{1/2}):

\left(\sqrt{\dfrac{\cos(2x)}{1+\sin(2x)}}\right)'=\dfrac1{2\sqrt{\frac{\cos(2x)}{1+\sin(2x)}}}\left(\dfrac{\cos(2x)}{1+\sin(2x)}\right)'

Simplify the leading term as

\dfrac1{2\sqrt{\frac{\cos(2x)}{1+\sin(2x)}}}=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}

Quotient rule:

\left(\dfrac{\cos(2x)}{1+\sin(2x)}\right)'=\dfrac{(1+\sin(2x))(\cos(2x))'-\cos(2x)(1+\sin(2x))'}{(1+\sin(2x))^2}

Chain rule:

(\cos(2x))'=-\sin(2x)(2x)'=-2\sin(2x)

(1+\sin(2x))'=\cos(2x)(2x)'=2\cos(2x)

Put everything together and simplify:

\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{(1+\sin(2x))(-2\sin(2x))-\cos(2x)(2\cos(2x))}{(1+\sin(2x))^2}

=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{-2\sin(2x)-2\sin^2(2x)-2\cos^2(2x)}{(1+\sin(2x))^2}

=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{-2\sin(2x)-2}{(1+\sin(2x))^2}

=-\dfrac{\sqrt{1+\sin(2x)}}{\sqrt{\cos(2x)}}\dfrac{\sin(2x)+1}{(1+\sin(2x))^2}

=-\dfrac{\sqrt{1+\sin(2x)}}{\sqrt{\cos(2x)}}\dfrac1{1+\sin(2x)}

=-\dfrac1{\sqrt{\cos(2x)}}\dfrac1{\sqrt{1+\sin(2x)}}

=\boxed{-\dfrac1{\sqrt{\cos(2x)(1+\sin(2x))}}}

5 0
3 years ago
Solve for x in simplest form 15 = 1/3(x+9)
Lorico [155]

Heya!

Your question states: Solve for x in simplest form 15 = 1/3(x+9)

Answer: X = 36

<em>Numerical Explanation:</em>

1. Step by step

   I. 15 = 1/3(x+9)

2. Simplify both sides of the equation:

    II. 15 = 1/3x + 3

3. Flip the equation:

      III. 1/3x + 3 = 15

4. Subtract 3 from both sides:

          IV. 1/3 x +3 = 15

                          -3    -3

5.  Multiply both sides by 3:

              V.  3 * (1/3 x) = (3) * (12)

6. Final answer:

                  VI. x = 36


I Hoped I Helped!


~KINGJUPITER

         


6 0
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KiRa [710]

Answer:

g=12

Step-by-step explanation:

substitute m for 6 and rewrite the equation

g = 6+6

g=12

3 0
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