Answer:
![M=0.294M](https://tex.z-dn.net/?f=M%3D0.294M)
Explanation:
Hello!
In this case, since the molarity of the iodide ion is computed by dividing the moles of iodide ions by the volume of solution in liters (0.150 L), we first need to compute the moles of zinc iodide (ZnI2) by using its molar mass and then using a mole ratio of 1 mol of zinc iodide to 2 mol of iodide ion:
![n_{I^-}=7.05gZnI_2*\frac{1molZnI_2}{319.22 gZnI_2}*\frac{2molI^-}{1molZnI_2}=0.0442molI^-](https://tex.z-dn.net/?f=n_%7BI%5E-%7D%3D7.05gZnI_2%2A%5Cfrac%7B1molZnI_2%7D%7B319.22%20gZnI_2%7D%2A%5Cfrac%7B2molI%5E-%7D%7B1molZnI_2%7D%3D0.0442molI%5E-)
Therefore, the resulting molarity turns out:
![M=\frac{0.0442molI^-}{0.150L} \\\\M=0.294M](https://tex.z-dn.net/?f=M%3D%5Cfrac%7B0.0442molI%5E-%7D%7B0.150L%7D%20%5C%5C%5C%5CM%3D0.294M)
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When it reaches the boiling point. When a substance reaches their boiling point, they change from liquid state to vapor state. Alcohol has a boiling point of around 78°C, so when you heat liquid alcohol to that temperature, it'll change to vapor.
Answer:
Would be increasing the concentration of SO3 as you chose in the question.
Explanation:
Increasing the concentration of the reactant will most likely shift it to the right by adding more products.