Answer:
acid
Explanation:
Methyl acetate, also known as MeOAc, acetic acid methyl ester or methyl ethanoate, is a carboxylate ester with the formula CH3COOCH3. It is a flammable liquid with a characteristically pleasant smell reminiscent of some glues and nail polish removers.
The combustion reaction is as expressed,
CxHy + O2 --> CO2 + H2O
The mass fraction of carbon in CO2 is 3/11. Hence,
mass of C in CO2 = (3.14 g)(3/11) = 0.86 g C.
Given that we have 1 g of the hydrocarbon, the mass of H is equal to 0.14 g.
moles of C = 0.86 g C / 12 g = 0.0713
moles of H = 0.14 g H / 1 g = 0.14
The empirical formula for the hydrocarbon is therefore, CH₂.
Answer:
116.88g of table salt (NaCl) contains two formula units
Explanation:
Now,
We know that 1 formula unit of sodium chloride has a molar mass of 58.44g/mol
Hence;
Mass of 1 formula unit = 58.44g
Mass of x formula units = 116.88g
x = 116.88g * 1 formula unit/58.44g
x = 2 formula units
Therefore;
116.88g of table salt (NaCl) contains two formula units
Hi. 2fouls! :)
First convert the number from kilometer to miles:


Now to find the miles per minutes,divide the miles per hours by 60 (the amount of minutes in an hour.)


The car is travelling at a speed of 0.860766667 miles/minute.
Hope this helps.
-Benjamin
The new concentrations of
and
are 0.25M and 19M
Calculation of number of moles of each component,
Molarity of
= number of moles/volume in lit = 0. 500 M
Number of moles = molarity of
× volume in lit = 0. 500 M× 0.025 L
Number of moles of
= 0.0125 mole
Molarity of
= number of moles/volume in lit = 0. 38 M
Number of moles = molarity of
× volume in lit = 0. 38 M× 0.025 L
Number of moles of
= 0.95 mole
Calculation of new concentration at volume 50 ml ( 0.05L)
Molarity of
= number of moles/volume in lit = 0.0125 mole/0.05L
Molarity of
= 0.25M
Molarity of
= number of moles/volume in lit = 0.95mole/0.05L
Molarity of
= 19 M
learn about Molarity
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