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3 years ago

Help me pls and can u also explain if u want

Mathematics

2 answers:

Dafna1 [17]3 years ago

8 0

Everything is "=" except 5/12.

Good luck! :)

Bingel [31]3 years ago

8 0

7/8 = 14:16
As 7×2=14 and 8×2=16
2/5 = 4:10
As 2×2=4 and 5×2=10
5/12 = 15:36
As 5×3=15 and 12×3=36
36/48 = 3:4
As 36÷3=12 and 48÷4=12

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What is the area of the model in the problem?

nata0808 [166]

Answer:

$A=x^2+12x+27\ units^2$

Step-by-step explanation:

we know that

The area of the model is equal to the area of a rectangle

The area of a rectangle is equal to

$A=LW$

we have

$L=x+9\ units$

$W=x+3\ units$

substitute

$A=(x+9)(x+3)$

Apply distributive property

$A=x^2+3x+9x+27$

Combine like terms

$A=x^2+12x+27\ units^2$

4 0

3 years ago

Someone please help

julia-pushkina [17]

Answer:

(a) So the top of the hill is 365 feet above sea level.

(b) Checkpoint 5 is 185 feet higher than checkpoint 2.

Step-by-step explanation:

Solution for (a):

Checkpoint 2 is -218 feet above sea level.

The top of a hill rises 583 feet above Checkpoint 2.

The altitude of the top of the hill = -218 + 583 = 365

So the top of the hill is 365 feet above sea level.

Solution for (b):

Checkpoint 2 is -218 feet above sea level.

Checkpoint 5 is -33 feet above sea level.

Checkpoint 5 is -33 - -218 = 185 feet higher than checkpoint 2.

3 0

3 years ago

The value of 5 in 506712 is how many times the value of 5 in 324859

Oxana [17]

It is 1.55 times the value of the second number.

8 0

3 years ago

Read 2 more answers

Adele ya tiene 2 pegatinas y obtendrá 21 pegatinas adicionales de cada paquete de pegatinas que compre. ¿Cuántos paquetes de peg

Zolol [24]

Answer:

Step-by-step explanation:

Tienen 15 hojas de pegatinas en total.

3 0

3 years ago

Refer to the following scenario:You want to see if there is a difference between the exercise habits of Science majors and Math

bekas [8.4K]

Answer:

1. H0: P1 = P2

2. Ha: P1 ≠ P2

3. pooled proportion p = 0.542

4. P-value = 0.0171

5. The null hypothesis failed to be rejected.

At a signficance level of 0.01, there is not enough evidence to support the claim that there is significant difference between the exercise habits of Science majors and Math majors .

6. The 99% confidence interval for the difference between proportions is (-0.012, 0.335).

Step-by-step explanation:

We should perform a hypothesis test on the difference of proportions.

As we want to test if there is significant difference, the hypothesis are:

Null hypothesis: there is no significant difference between the proportions (p1-p2 = 0).

Alternative hypothesis: there is significant difference between the proportions (p1-p2 ≠ 0).

The sample 1 (science), of size n1=135 has a proportion of p1=0.607.

$p_1=X_1/n_1=82/135=0.607$

The sample 2 (math), of size n2=92 has a proportion of p2=0.446.

$p_2=X_2/n_2=41/92=0.446$

The difference between proportions is (p1-p2)=0.162.

$p_d=p_1-p_2=0.607-0.446=0.162$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{82+41}{135+92}=\dfrac{123}{227}=0.542$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.542*0.458}{135}+\dfrac{0.542*0.458}{92}}\\\\\\s_{p1-p2}=\sqrt{0.001839+0.002698}=\sqrt{0.004537}=0.067$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.162-0}{0.067}=\dfrac{0.162}{0.067}=2.4014$

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

$\text{P-value}=2\cdot P(z>2.4014)=0.0171$

As the P-value (0.0171) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

At a signficance level of 0.01, there is not enough evidence to support the claim that there is significant difference between the exercise habits of Science majors and Math majors .

We want to calculate the bounds of a 99% confidence interval of the difference between proportions.

For a 99% CI, the critical value for z is z=2.576.

The margin of error is:

$MOE=z \cdot s_{p1-p2}=2.576\cdot 0.067=0.1735$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = 0.162-0.1735=-0.012\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= 0.162+0.1735=0.335$

The 99% confidence interval for the difference between proportions is (-0.012, 0.335).

6 0

3 years ago