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madam [21]
2 years ago
11

If a pair of linear equations is consistent, then the lines will be

Mathematics
1 answer:
Lesechka [4]2 years ago
8 0
C
Intersecting or coincident
If a pair of linear equation is consistent, then it has unique solutions and infinity solutions.
For unique solution-
⇒
a
2
​

a
1
​

​


=
b
2
​

b
1
​

​

∴ the lines will be intersecting.
For infinity solution-
⇒
b
1
​

a
1
​

​
=
b
2
​

b
1
​

​
=
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26/x=-13 <br> I need a false answer and what it would equil
cupoosta [38]
Correct answer:
26 = -13x
X = -2

if you need a false answer, make up any number!
7 0
1 year ago
Expand and simplify (x+2)(x+4)(x+6)
Deffense [45]

Answer:

Multiply the first two binomials: (x+2) & (x+4) using the FOIL method (First, Outer, Inner & Last).

(x+2)(x+4) = x^² + 4x + 2x + 8 = x^² + 6x + 8

Then we multiply the trinomial that we got from the first stage and multiply that by the remaining binomial:

(x^² + 6x + 8) (x + 4)

= x^³ + 4x^² + 6x^² + 24x + 8x + 32

Collect the like terms together to give you:

x^³ + 10x^² + 32x + 32

5 0
2 years ago
Jamilia has a weather station in her backyard. She uses a rain gauge to track the total rainfall during two storms.
Zielflug [23.3K]

Answer:

1) The graph is linear, because it has an upwards slope of 5, we can tell because 3*5 =15 and 6*5=30.  

2)Real world meaning is the delta change. Hence in this case it's the increase in rain over time. More rain or raining harder as time progresses.

3)It is not linear because the second sample shows a slope of 7.5 meanwhile the third sample shows a slope of 6 which allows us to conclude that it is not linear.

4)The y intercept means the total rain that was present at the start of the recording which essentially means there was no rain when she started the experiment.

3 0
3 years ago
Find the sum of the convergent series. (round your answer to four decimal places. ) [infinity] (sin(9))n n = 1
Alexus [3.1K]

The sum of the convergent series \sum_{n=1}^{\infty}~(sin(1))^n is 5.31

For given question,

We have been given a series \sum_{n=1}^{\infty}~(sin(1))^n

\sum_{n=1}^{\infty}~(sin(1))^n=sin(1)+(sin(1))^2+...+(sin(1))^n

We need to find the sum of given convergent series.

Given series is a geometric series with ratio r = sin(1)

The first term of the given geometric series is a_1=sin(1)

So, the sum is,

= \frac{a_1}{1-r}

= sin(1) / [1 - sin(1)]

This means, the series converges to sin(1) / [1 - sin(1)]

\sum_{n=1}^{\infty}~(sin(1))^n

= \frac{sin(1)}{1-sin(1)}

= \frac{0.8415}{1-0.8415}

= \frac{0.8415}{0.1585}

= 5.31

Therefore, the sum of the convergent series \sum_{n=1}^{\infty}~(sin(1))^n is 5.31

Learn more about the convergent series here:

brainly.com/question/15415793

#SPJ4

7 0
1 year ago
Please help me with these questions.
Debora [2.8K]
4. k less than 3.5, so a number k is being taken away from 3.5:
The answer is 3.5-k

5. the sum of g and h, reduced by 11, so you need a set of parentheses to write this one: (g+h)-11

6. 5 less than y, plus g, so do a combination of the strategies used in the previous two problems and you will get: (y-5)+g

7. 5 less than the sum of y and g, you are taking away 5 from the sum of two numbers, y and g, so: (y+g)-5

Hope this helps :-)
5 0
3 years ago
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