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3 years ago

Which of the following is equivalent to log (2x - 5) = 4

Mathematics

1 answer:

Vladimir [108]3 years ago

5 0

Answer:

option d is equivalent to the term

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1) Eight less than triple a number

marta [7]

1) 3x-8 =x
subtract x from both sides
2x-8=0
add 8 to each side
2x=8
divide both sides by 2

x=4

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3 years ago

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AlexFokin [52]

The answer is 7 because you are dividing the output to the input you will get 8 for each so therefore you divide 56 by 8 to get 7

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lara31 [8.8K]

Answer:

Step-by-step explanation:

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How do you turn 0.79 into a fraction?

Gemiola [76]

0.79 = 79/100 . . .

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4 years ago

Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I

Elden [556K]

Answer:

$Time = 11\frac{2}{3}\ min$

Step-by-step explanation:

Given

$Security\ A = 2\ mins, 20\ secs$

$Security\ B = 1\ mins, 40\ secs$

Required

After how many minutes, will they round together

First, convert the given time to minutes

$Security\ A = 2\ mins, 20\ secs$

$Security\ A = 2\ mins+ 20\ secs$

$Security\ A = 2\ mins+ \frac{20}{60}\ min$

$Security\ A = 2\ mins+ \frac{1}{3}\ min$

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\ mins, 40\ secs$

$Security\ B = 1\ mins+ 40\ secs$

$Security\ B = 1\ mins+ \frac{40}{60}\ min$

$Security\ B = 1\frac{2}{3}\ min$

So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

<em>This implies that they go on round after </em> $11\frac{2}{3}\ min$ <em></em>

4 0

3 years ago