Assume that the number of adult tickets is a and the number of child tickets is c.
We are given that the adult ticket is sold for 20$, the child ticket is sold for 10$ and that the total is $15,000. This means that:
20a + 10c = 15,000 ..........> equation I
We are also given that number of child tickets is 3 times that of adult's. This means that:
c = 3a .........> equation II
Substitute with equation II in equation I to get a as follows:
20a + 10c = 15,000
20a + 10(3a) = 15,000
20a + 30a = 15,000
50a = 15,000
a = 300 tickets
Substitute with the value of a in equation II to get c as follows:
c = 3a
c = 3(300)
c = 900 tickets
Based on the above calculations,
number of child tickets = 900 ticket
number of adult tickets = 300 ticket
8(4a+2b)
The equivalent is 32a+16b (B)
Answer:
True
Step-by-step explanation:
First, we need to recognize that
Now, we can try to solve
Multiply each side by 
As we end up with an answer that cannot be true, we know that there is no solution.
Another method to solve this would be graphing the function 
When graphed, it can be seen that there is an asymptote at x=0 meaning that there is no value for x=0.
Answer:
7
Step-by-step explanation:
2-(-8)+(-3)
2+8-3
10-3
7
The correct answer is B) -0.3
Z-scores are found using the formula
z = (X-μ)/σ
For this problem, we have
z = (24-24.5)/1.7 = -0.5/1.7 = -0.3
