Ask question

Ask question

All categories

2 years ago

5

16. WalkieTalkie phone company charges $18.00 for basic phone service per month and $0.15 per minute for long distance calls. Ar

ena Calls charges $80.00 per month with no fee for long distance calls. What is the minimum number of minutes of long distance calls for which the cost of Walkie Talkie is more than the cost of Arena Calls?

1 answer:

8090 [49]2 years ago

6 0

Answer:

413 minutes of long distance calls

Step-by-step explanation:

$80.00 - $18.00 = $62.00

$62.00/$0.15 = 413.33

You might be interested in

In order to qualify for a role in a play, an actor must be taller than 64 inches but shorter than 68 inches. The inequality 64 &

netineya [11]

Answer: x > 64 and x < 68 is another way of rewriting inequality.

Step-by-step explanation:

To qualify for a role in a play, an actor must be taller than 64 inches but shorter than 68 inches.

⇒The inequality 64 < x < 68, where x represents height,gives the range of height.

⇒In other words range of height can be x > 64 and x < 68 , such that both conditions are applied to single actor.

[with the use of or it will appear to give priority by actor to follow any 1 conditon]

8 0

1 year ago

What can you conclude from her work? Check all that apply.

enot [183]

Answer:

first, third and last one

Step-by-step explanation:

10 0

3 years ago

Read 2 more answers

What is the equation for x in the diagram ?

mrs_skeptik [129]

I believe the answer is a.

7 0

3 years ago

50 PTS ANSWER ALL <3333333

11Alexandr11 [23.1K]

QUESTION 33

The length of the legs of the right triangle are given as,

6 centimeters and 8 centimeters.

The length of the hypotenuse can be found using the Pythagoras Theorem.

${h}^{2} = {6}^{2} + {8}^{2}$

${h}^{2} = 36+ 64$

${h}^{2} = 100$

$h = \sqrt{100}$

$h = 10cm$

Answer: C

QUESTION 34

The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.

The length of the other leg can be found using the Pythagoras Theorem,

${l}^{2} + {33}^{2} = {55}^{2}$

${l}^{2} = {55}^{2} - {33}^{2}$

${l}^{2} = 1936$

$l = \sqrt{1936}$

$l = 44cm$

Answer:B

QUESTION 35.

We want to find the distance between,

(2,-1) and (-1,3).

Recall the distance formula,

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the values to get,

$d=\sqrt{( - 1-2)^2+(3- - 1)^2}$

$d=\sqrt{( - 3)^2+(4)^2}$

$d=\sqrt{9+16}$

$d=\sqrt{25}$

$d = 5$

Answer: 5 units.

QUESTION 36

We want to find the distance between,

(2,2) and (-3,-3).

We use the distance formula again,

$d=\sqrt{( - 3-2)^2+( - 3- 2)^2}$

$d=\sqrt{( - 5)^2+( - 5)^2}$

$d=\sqrt{25+25}$

$d=\sqrt{50}$

$d=5\sqrt{2}$

Answer: D

8 0

2 years ago

Read 2 more answers

3-18 even problems algebra 1 math

Tresset [83]

The answers for problems 13-18 are -9, 8, -2, 5, -2, and 15 after equating the same functions.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

It is given that:

From problems 13 - 18, some functions are shown,

13) h(x) = -7x, h(x) = 63

Equate both the function:

-7x = 63

x = -9

14) t(x) = 3x, t(x) = 24

Equate both the function:

3x = 24

x = 8

15) m(x) = 4x + 15, m(x) = 7

4x + 15 = 7

4x = -8

x = -2

16) 6x - 12 = 18

x = 5

17) 1/2 x - 3 = -4

1/2 x = -1

x = -2

18) j(x) = -4/5 x + 7, j(x) = -5

-4/5 x + 7 = -5

-4/5 x = -12

x = 15

Thus, the answers for problems 13-18 are -9, 8, -2, 5, -2, and 15 after equating the same functions.

Learn more about the function here:

brainly.com/question/5245372

#SPJ1

7 0

7 months ago