The transformation is done to y=1/x to get y=1/4x-12. We defined a turning point in the equation which will indicate the point in the graph.

We changed the form from y=x to y=x+c. In this case, we use 1/2 for the and constant C value which is -12.

3 0

3 years ago

HELP ASAP

denis-greek [22]

A) I included a graph, look below.

B)

Input the y in x = y + 3.

x = (-4x - 3) + 3
x = -4x + 0
Add 4x to both sides.
5x = 0
Divide both sides by 5.
x = 0

Input that x value in y = -4x - 3

y = -4(0) - 3
y = 0 - 3
y = -3

(0, -3)

C)

Convert both equations to Standard Form.

x = y + 3
Subtract y from both sides.
x - y = 3

y = -4x - 3
Add 4x to both sides.
4x + y = -3

Add the equations together.

4x + y = -3
x - y = 3
equals
5x = 0
Divide both sides by 5.
x = 0

Input that into one of the original equations.

0 = y + 3
Subtract 3 from both sides.
-3 = y

(0, -3)

7 0

2 years ago

Tickets to a local circus cost $5 for students and $8 for adults. A group of 9 people spent a total of $60. How many adults were

S_A_V [24]

Answer:

Step-by-step explanation:

You need to set up and solve a system of linear equations here.

Let s and a represent the number of students and adults respectively.

Then s + a = 9, and s = 9 - a.

Total ticket cost for the adults was ($8/adult)(a)

and for the students ($5/student)(s).

Total cost of the tickets was then ($8/adult)(a) + ($5/student)(s) = $60.

Then our system of linear equations is:

8a + 5s = 60

a + s = 9, or s = 9 - a. Substituting 9 - a for s, we get:

8a + 5(9 - a) = 60.

Then 8a + 45 - 5a = 60, or 3a = 15.

Solving for a, we get a = 5.

Solving for s using s = 9 - a, we get s = 9 - 5, or s = 4.

There were 5 adults in the group (and 4 students).

3 0

3 years ago