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melisa1 [442]
3 years ago
6

Find four consecutive natural numbers if you know that the product of the first two is 38 less than the product of the following

two numbers.
Mathematics
2 answers:
Fynjy0 [20]3 years ago
8 0
<span>Because the four numbers are consecutive, we can call the first one x, and the other three are x+1, x+2, and x+3, respectively. x * (x+1) = (x+2) * (x+3) - 38 x^2 + x = x^2 + 5x +6-38 x^2 + x = x^2 + 5x - 32 -4x = -32 x=8 The four numbers are 8, 9, 10, and 11 check solution: 8*9=10*11-38 72=110-38 72=72</span>
fenix001 [56]3 years ago
4 0

Answer:

8,9,10,11

Step-by-step explanation:

Let

x------> first natural number

x+1 ---> second consecutive natural number

x+2 ---> third consecutive natural number

x+3 ---> fourth consecutive natural number

we know that

x(x+1)=(x+2)(x+3)-38

x^{2}+x=x^{2}+3x+2x+6-38  

x^{2}+x=x^{2}+5x+6-38

5x-x+6-38=0

4x=32

x=8

therefore

The numbers are

8,9,10,11

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