Question

Find four consecutive natural numbers if you know that the product of the first two is 38 less than the product of the following two numbers.

Answer 1

Because the four numbers are consecutive, we can call the first one x, and the other three are x+1, x+2, and x+3, respectively. x * (x+1) = (x+2) * (x+3) - 38 x^2 + x = x^2 + 5x +6-38 x^2 + x = x^2 + 5x - 32 -4x = -32 x=8 The four numbers are 8, 9, 10, and 11 check solution: 8*9=10*11-38 72=110-38 72=72

Answer 2

Answer:

$8,9,10,11$

Step-by-step explanation:

Let

x------> first natural number

x+1 ---> second consecutive natural number

x+2 ---> third consecutive natural number

x+3 ---> fourth consecutive natural number

we know that

$x(x+1)=(x+2)(x+3)-38$

$x^{2}+x=x^{2}+3x+2x+6-38$  

$x^{2}+x=x^{2}+5x+6-38$

$5x-x+6-38=0$

$4x=32$

$x=8$

therefore

The numbers are

$8,9,10,11$