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3 years ago

67% as a fraction in simplest form

Mathematics

2 answers:

otez555 [7]3 years ago

7 0

67/100 That is the simplest form

CaHeK987 [17]3 years ago

6 0

It's 67/100 because a percent is out of 100 which is already simplified

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Find the surface area of each figure to the nearest tenth.

Stells [14]

For the cylinder on the left-hand-side,

$\bf \textit{surface area of a cylinder}\\\\
S=2\pi r(h+r)\quad 
\begin{cases}
r=radius\\
h=height\\
------\\
h=10\\
r=5
\end{cases}\implies S=2\pi (5)(10+5)$

now, for the triangular prism on the right-hand-side,

notice is really just 2 triangles and 3 rectangles, stacked up to each other at the edges.

the triangles have a base of 4, and a height of 1.5.

the rectangle on the left and the one on the right is a 6x2.5 rectangle.

the rectangle at the bottom, is a 4x6 rectangle.

adding their areas, is the area of the prism,

$\bf \stackrel{two~triangles}{2\left[\cfrac{1}{2}(4)(1.5) \right]}+\stackrel{left-right~rectangles}{2(6\cdot 2.5)}+\stackrel{bottom~rectangle}{4\cdot 6}
\\\\\\
6~~+~~30~~+~~24$

7 0

4 years ago

Find the area of circle o if DCBO is a rectangle and DB measure 10 units

Dmitrij [34]

Answer:

$100\pi$

Step-by-step explanation:

Step 1: Identity the radius.

Since O is the center of the circle, and C and E lie on the circumference, OC and OE are the radii of the circle and thus,

OC=OE.

Step 2: Consider the rectangle.

All diagonals in a rectangle are congruent so this means

DB= OC ( OC is also a diagonal).

Thus, OC= 10 units.

Step 3: Analyze

So this means OE is also 10 units as well.

Since we know the length of the radius, Use the area of circle,

$\pi {r}^{2}$

$\pi( {10}^{2} ) = 100\pi$

So the area of a circle is 100 pi.

3 0

2 years ago

Read 2 more answers

Given cosα = −3/5, 180 < α < 270, and sinβ = 12/13, 90 < β < 180

torisob [31]

I got

$- \frac{6 3}{65}$

What we know

cos a=-3/5.

sin b=12/13

Angle A interval are between 180 and 270 or third quadrant

Angle B quadrant is between 90 and 180 or second quadrant.

What we need to find

Cos(b)

Cos(a)

What we are going to apply

Sum and Difference Formulas

Basics Sine and Cosines Identies.

1. Let write out the cos(a-b) formula.

$\cos(a - b) = \cos(a) \cos(b) + \sin(a) \sin(b)$

2. Use the interval it gave us.

According to the given, Angle B must between in second quadrant.

Since sin is opposite/hypotenuse and we are given a sin b=12/13. We. are going to set up an equation using the pythagorean theorem.

${12}^{2} + {y}^{2} = {13}^{2}$

$144 + {y}^{2} = 169$

$25 = {y}^{2}$

$y = 5$

so our adjacent side is 5.

Cosine is adjacent/hypotenuse so our cos b=5/13.

Using the interval it gave us, Angle a must be in the third quadrant. Since cos is adjacent/hypotenuse and we are given cos a=-3/5. We are going to set up an equation using pythagorean theorem,

$( - 3) {}^{2} + {x}^{2} = {5}^{2}$