Answer:
In D
Step-by-step explanation:
in d you can place the lamp there
Answer:

Step-by-step explanation:

Lets expand all the composite numbers into prime numbers.

Lets cancel
from numerator and denominator.

Using laws of exponents , lets solve this.


![=> 3^{-3} \times 5^{[1 - (-2)]}](https://tex.z-dn.net/?f=%3D%3E%203%5E%7B-3%7D%20%5Ctimes%205%5E%7B%5B1%20-%20%28-2%29%5D%7D)


Answer:
14x-2 is answer
Step-by-step explanation:
may be this is helpful!
Answer:
D.
Step-by-step explanation:
