Answer: 45?
Step-by-step explanation: Sorry If I'm wrong, I haven't learned this yet but I tried my best.
So distribute using distributive property
a(b+c)=ab+ac so
split it up
(5x^2+4x-4)(4x^3-2x+6)=(5x^2)(4x^3-2x+6)+(4x)(4x^3-2x+6)+(-4)(4x^3-2x+6)=[(5x^2)(4x^3)+(5x^2)(-2x)+(5x^2)(6)]+[(4x)(4x^3)+(4x)(-2x)+(4x)(6)]+[(-4)(4x^3)+(-4)(-2x)+(-4)(6)]=(20x^5)+(-10x^3)+(30x^2)+(16x^4)+(-8x^2)+(24x)+(-16x^3)+(8x)+(-24)
group like terms
[20x^5]+[16x^4]+[-10x^3-16x^3]+[30x^2-8x^2]+[24x+8x]+[-24]=20x^5+16x^4-26x^3+22x^2+32x-24
the asnwer is 20x^5+16x^4-26x^3+22x^2+32x-24
Answer:
27 chocolate cake and 12 pecan cake
Step-by-step explanation:
Answer: 9
Step-by-step explanation:
We will use the Order of Operations to solve.
Given:
4 – 15 ÷ (30 – 33)
Subtract 33 from 30:
4 – 15 ÷ (– 3)
Divide -15 by -3:
4 + 5
Add 4 to 5:
9
