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Marina CMI [18]
3 years ago
13

Which of the lists of letters all have line symmetry?

Mathematics
2 answers:
babymother [125]3 years ago
8 0
<h3>Answer:  1. (A, B, C, D)</h3>

==================================================

Explanation:

Check out the diagram below to see where the lines of symmetry are located.

For the letter A, we have a vertical line through the center that is the mirroring line. Reflecting one half over that line generates the other half.

For letter B, we have a horizontal line through the center. This applies to letters C and D as well.

This is why answer choice 1 is the final answer.

-----------

For letter Z, we have neither a vertical nor a horizontal mirror line. This letter doesn't have any lines of symmetry (though it does have rotational symmetry). So we can rule out answer choice 2.

Letter N is pretty much the same idea as letter Z. There aren't any lines of symmetry but we do have rotational symmetry. So we can rule out answer choice 3.

Lastly, we can rule out answer choice 4 because letter S has the same properties as letters Z and N.

Sunny_sXe [5.5K]3 years ago
6 0

Answer:

The first row

Step-by-step explanation:

Letters A,B,C,D

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g In a certain rural county, a public health researcher spoke with 111 residents 65-years or older, and 28 of them had obtained
Marat540 [252]

Answer:

95% confidence interval for the percent of the 65-plus population that were getting the flu shot is [0.169 , 0.331].

Step-by-step explanation:

We are given that in a certain rural county, a public health researcher spoke with 111 residents 65-years or older, and 28 of them had obtained a flu shot.

Firstly, the Pivotal quantity for 95% confidence interval for the population proportion is given by;

                          P.Q. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of residents 65-years or older who had obtained a flu shot = \frac{28}{111} = 0.25

          n = sample of residents 65-years or older = 111

          p = population proportion of residents who were getting the flu shot

<em>Here for constructing 95% confidence interval we have used One-sample z test for proportions.</em>

<u>So, 95% confidence interval for the population proportion, p is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } },\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

   = [ 0.25-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{111} } } , 0.25+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{111} } } ]

   = [0.169 , 0.331]

Therefore, 95% confidence interval for the percent of the 65-plus population that were getting the flu shot is [0.169 , 0.331].

7 0
3 years ago
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8 0
2 years ago
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Helps please does that look right to y’all ?
ladessa [460]
<h3>You have the correct answer</h3><h3>Interest rate = 21.5%</h3>

===============================================

Work Shown:

i = P*r*t .... simple interest formula

i = simple interest

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i = P*r*t

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1075 = 5000r

5000r = 1075

r = 1075/5000

r = 0.215

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