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zysi [14]
3 years ago
11

Which of the following correctly uses absolute value to show the distance between −60 and 13? (5 points)

Mathematics
1 answer:
ioda3 years ago
7 0

A.)|−60 − 13| = |−73| = 73 units is the answer

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What is the definition of math
RideAnS [48]

Ya sure....

Just wait......

Have a beautiful and joyful day ahead.

6 0
3 years ago
The one above me is right
igomit [66]
Huh? What’s above it?
6 0
3 years ago
Cindy is facing South through how many degrees should she turn clockwise to face East? a. 90° b. 180° c. 270° d. 360° e. Other:
julia-pushkina [17]

Answer:

90°

Step-by-step explanation:

because from south to east is half of north which makes it 90°

4 0
3 years ago
Let us analyze the following setting. You are given a circle of unit circumference. You pickkpoints on the circle independently
garik1379 [7]

Answer:

We have been given a unit circle which is cut at k different points to produce k different arcs. Now we can see firstly that the sum of lengths of all k arks is equal to the circumference:

\small \sum_{i = 1}^{k} L_i= 2\pi

Now consider the largest arc to have length \small l . And we represent all the other arcs to be some constant times this length.

we get :

 \small \sum_{i = 1}^{k} C_i.l = 2\pi

where C(i) is a constant coefficient obviously between 0 and 1.

\small \sum_{i = 1}^{k} C_i= 2\pi/l

All that I want to say by using this step is that after we choose the largest length (or any length for that matter) the other fractions appear according to the above summation constraint. [This step may even be avoided depending on how much precaution you wanna take when deriving a relation.]

So since there is no bias, and \small l may come out to be any value from [0 , 2π] with equal probability, the expected value is then defined as just the average value of all the samples.

We already know the sum so it is easy to compute the average :

\small L_{Exp} = \frac{2\pi}{k}

7 0
3 years ago
Whats the answer to 3,000(6-2) + 3,000
yuradex [85]
The answer is 15000

3000 \times ( 6 - 2) = 12000  + 3000 = 15000
3000*6=1800
3000*-2=-6000
18000-6000=12000
12000+3000=15000
8 0
4 years ago
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