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3 years ago

30% of which number is 3? O A. 10 B. 9 O c. 1 O D. 0.9 O E. 0.1

Mathematics

2 answers:

natima [27]3 years ago

6 0

Answer:

The answer is B. Hope this helps!

alina1380 [7]3 years ago

4 0

Answer:

The answer is letter D

Step-by-step explanation:

3 x 0.30 = 0.9

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When building a mini-boat, a boat builder uses 2 pounds of wood and 3 ounces of glue. If he/she has 3 pounds of wood and 6 ounce

zepelin [54]

Answer:

Step-by-step explanation:

It means that every unit of mini boat requires 2 pounds of wood and 3 ounces of glue.

As such 3 pounds of wood can only be used to build one mini boat and there will be one pound of wood left. With 6 ounces of gold, the builder can build 2 boats (6/3).

However, the wood becomes the limiting factor that determines the number of mini-boats that can be made. Hence with 3 pounds of wood and 6 ounces of glue, the builder can only build a mini-boat.

4 0

3 years ago

Read 2 more answers

Jessica is a custodian at Oracle Arena. She waxes 20 m² of the floor in = of an hour. Jessica

Wewaii [24]

The complete question is as follows:

Jessica is a custodian at Oracle Arena. She waxes 20 $\mathbf{m^{2}}$ of the floor in $\mathbf{\frac{3}{5}}$ of and hour. At this rate, how many square meters can she wax per hour ?

Answer:

$\mathbf{\frac{100}{3}\approx33.33 \ m^{2} \ per \ hour}$

Step-by-step explanation:

$\textrm{rate}=\frac{\textrm{Area waxed in square meter}}{\textrm{Time taken to wax in hours}}$

$\textrm{rate}=\frac{20 \ \textrm{m}^{2}}{\frac{3}{5} \ \textrm{hours}}$

$\textrm{rate}=\frac{20\times5}{3}$

$\mathbf{rate=\frac{100}{3}\approx33.33 \ m^{2} \ per \ hour}$

8 0

3 years ago

A company manufactures televisions. The average weight of the televisions is 5 pounds with a standard deviation of 0.1 pound. As

Semenov [28]

Answer:

$0.2564\text{ pounds}$

Step-by-step explanation:

The 90th percentile of a normally distributed curve occurs at 1.282 standard deviations. Similarly, the 10th percentile of a normally distributed curve occurs at -1.282 standard deviations.

To find the $X$ percentile for the television weights, use the formula:

$X=\mu +k\sigma$ , where $\mu$ is the average of the set, $k$ is some constant relevant to the percentile you're finding, and $\sigma$ is one standard deviation.

As I mentioned previously, 90th percentile occurs at 1.282 standard deviations. The average of the set and one standard deviation is already given. Substitute $\mu=5$ , $k=1.282$ , and $\sigma=0.1$ :