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cupoosta [38]
3 years ago
13

2x^4 +4x^3 - 5x^2 - 5x +6 how many zeros are imaginary

Mathematics
1 answer:
cricket20 [7]3 years ago
3 0

Answer:

4 zeros

Step-by-step explanation:

The zeroes of

f

(

x

)

=

2

x

4

−

5

x

3

+

3

x

2

+

4

x

−

6

are

x

=

−

1

,

x

=

3

2

,

x

=

1

−

i

, and

x

=

1

+

i

.

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Evaluate the given integral by changing to polar coordinates. 8xy dA D , where D is the disk with center the origin and radius 9
BabaBlast [244]

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0

Step-by-step explanation:

∫∫8xydA

converting to polar coordinates, x = rcosθ and y = rsinθ and dA = rdrdθ.

So,

∫∫8xydA = ∫∫8(rcosθ)(rsinθ)rdrdθ = ∫∫8r²(cosθsinθ)rdrdθ = ∫∫8r³(cosθsinθ)drdθ

So we integrate r from 0 to 9 and θ from 0 to 2π.

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Substituting this we have

13122∫(cosθsinθ)dθ = 13122∫(1/2)(sin2θ)dθ

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= -13122/4[1 - 1]

= -13122/4 × 0

= 0

5 0
3 years ago
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