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cupoosta [38]
2 years ago
13

2x^4 +4x^3 - 5x^2 - 5x +6 how many zeros are imaginary

Mathematics
1 answer:
cricket20 [7]2 years ago
3 0

Answer:

4 zeros

Step-by-step explanation:

The zeroes of

f

(

x

)

=

2

x

4

−

5

x

3

+

3

x

2

+

4

x

−

6

are

x

=

−

1

,

x

=

3

2

,

x

=

1

−

i

, and

x

=

1

+

i

.

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Will someone help me with this question plz?
Juli2301 [7.4K]
I attached a picture with the answer, hope this helps :)

7 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=16x%20-%20%288x%20%20%2B%206%29%20%3D90" id="TexFormula1" title="16x - (8x + 6) =90" alt="16x
Lina20 [59]

Answer:

x=12

Step-by-step explanation:

16x - (8x  + 6) =90

The first step is to distribute the - sign

16x -8x -6 =90

Now we combine the like terms

8x-6 = 90

Add 6 to each side

8x-6+6 = 90+6

8x = 96

Divide each side by 8

8x/8 = 96/8

x =12

8 0
3 years ago
Consider the following 8 numbers, where one labelled
AlladinOne [14]
<h3>Answers:     x = -17  and   x = 64</h3>

====================================================

Explanation

Consider three scenarios:

  • A) The value of x is the smallest of the set (aka the min)
  • B) The value of x is the largest of the set (aka the max)
  • C) The value of x is neither the min, nor the max. So 8 < x < 39.

These scenarios cover all the possible cases of what x could be. It's either the min, the max, or somewhere in between the min and max.

--------------------

We'll start with scenario A.

If x is the min, then that must mean 39 is the max as it's the largest of the set {18, 36, 16, 39, 27, 8, 34}

The range is 56, so,

range = max - min

56 = 39 - x

56+x= 39

x = 39-56

x = -17  which is one possible answer

--------------------

If instead we go with scenario B, then x is the max and 8 is the min

range = max - min

56 = x - 8

56+8 = x

64 = x

x = 64 is the other possible answer

--------------------

Lastly, let's consider scenario C. If x is not the min or the max, then it's somewhere between the min 8 and max 39. in short, 8 < x < 39.

Note that range = max - min = 39-8 = 31 which is not the range of 56 that we want. So there's no way scenario C can be possible here.

7 0
3 years ago
Simplify the expression <br><br><img src="https://tex.z-dn.net/?f=6%285%20%2B%20t%29%20-%203%28t%20%2B%203%29" id="TexFormula1"
Pavel [41]
30+6t - 3t-9
combine 6t and -3t and get 3t
30+3t=-9
subtract 30 on both sides
3t=-39
divide by 3
t=13
3 0
3 years ago
A line intersects the points (3,-4) and
MrRa [10]

Answer:

y = - 3x + 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁  )

with (x₁, y₁ ) = (3, - 4) and (x₂, y₂ ) = (1, 2)

m = \frac{2+4}{1-3} = \frac{6}{-2} = - 3, thus

y = - 3x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (1, 2), then

2 = - 3 + c ⇒ c = 2 + 3 = 5

y = - 3x + 5 ← equation of line

5 0
3 years ago
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