ANSWER
(2,-2)
(10,-10)
(2,-9)
(7,-10)
EXPLANATION
The given point is (2,-10)
This point is in the fourth quadrant.
To be able to use the number line to find the distance between this point , (2,-10) and another point in the fourth quadrant, the second point must have the same x-coordinate with this point or the same y-coordinate with this point.
These points are:
(2,-2)
(10,-10)
(2,-9)
(7,-10)
Check the picture below.
how do we know? well, notice h(t), starts off at 12, up up up reaches 47.84 then down down down, which is pretty much the trajectory of a flying object, by the time it gets to 44, is still going down.
now, let's look at g(t), starts off at 10, and goes up up up, never down, by the time it gets to 41, is still going up,
so at second 2, h(t) is 44 and going down, g(t) is 41 and going up, at 2.2 h(t) is 40.16, and g(t) is 44.1, between that lapse, h(t) became 44, 43, 42, 41, in the same lapse g(t) became 41, 42, 43, 44, so somewhere in those values h(t) = g(t).
what does the solution mean? It's the seconds or the instant lapse when the first cannon ball was at the same height as the second cannonball.
Radius = 5 cm
Height = 8 cm
Volume = πr²h
Volume = π(5 cm)² × 8 cm
Volume = π × 25 cm² × 8 cm
Volume = 200π cm³
Answer:
We are missing 210
Step-by-step explanation:
3*4 = 12
3*70 =210
3*300=900
We are missing 210
Answer:
0.504m
Step-by-step explanation:
First, we would multiply 0.4cm by 126 watermelon seeds to find the length of the line in cm.
0.4*126
= 50.4cm
Therefore, the line of watermelon seeds stretches 50.4cm.
Now, because the question wants us to type the answer in meters, we must convert 50.4cm into meters. We do this by dividing 50.4 by 100 since 100cm makes up 1 meter.
50.4/100
= 0.504m
Therefore, the line of watermelon seeds stretches 0.504m.
I hope this helps!
