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Julli [10]
3 years ago
11

Jim had 360 stamps. He sold 1/3 of them on Monday and 1/4 of the remainder on Tuesday. How many stamps did he sell on Tuesday

Mathematics
1 answer:
V125BC [204]3 years ago
5 0
First, you multiply 360 by 1/3, to give you 120. Then multiply 120 by 1/4. That give you 30. If you subtract 30 from 120, it gives you the answer that Jim sold 90 stamps on Tuesday.
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What is the additive inverse of the complex number –8 + 3i?
Lady bird [3.3K]
Choices:
–8 – 3i
–8 + 3i
8 – 3i
<span>8 + 3i

The additive inverse of the complex number a + bi is -(a+bi) = -a - bi

In this case, a = -8 and b = 3i

a + bi = -8 + 3i
additive inverse is:  -(-8+3i) = +8 - 3i

The additive inverse of the complex number -8 + 3i is 8 - 3i. The 3rd choice.


</span>
5 0
4 years ago
Read 2 more answers
Given: f(x) = x - 7 and h(x) = 2x + 3<br> Write the rule for f(h(x)).
sdas [7]
<h3>Answer:  f( h(x) ) = 2x - 4</h3>

Work Shown:

f(x) = x - 7

f( h(x) ) = h(x) - 7

f( h(x) ) = 2x+3 - 7

f( h(x) ) = 2x - 4

Explanation:

In the second step, I replaced every x with h(x). In the next step, I replaced the h(x) on the right hand side with 2x+3. From there I combined like terms.

8 0
3 years ago
Suppose Maya made another sign with an area of 48 square inches. Would this sign be larger or smaller than the sign with an area
luda_lava [24]
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6 0
3 years ago
What is the length of leg s of the triangle below?
vekshin1

Answer:

4 units

Step-by-step explanation:

Let ABC be isosceles right angled ∆ right angled at B

By Pythagoras theorem,

AC² = AB² + BC²

(√32)² = 4² + s²

32 = 16 + s²

s² = 32 - 16

s² = 16

s = √16

s = 4 units.

Therefore s = 4 units

Hope it helps...

6 0
3 years ago
How can you determine if a square root is completely simplified?
ycow [4]

Answer:

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Step-by-step explanation:

Okay, so I'm going to give an example of the simplifying process.

\sqrt{243}

If you were to just type this in to a calculator you would get 15.58 and so on, so that means we have to just simplify instead of solving for accuracy purposes.

So take 243 and divide it by a number that can go into it equally. I'm going use 3. When you do that you get 81. Usually when I do this I draw it out to better see it, so I'm going to try for you. The 3 is prime so we can't simplify that term anymore, but you can still simplify the 81, so that is what we do next. I'm going to use 3 to make it easier in the end results. Notice 3 is prime but 27 still is not, so we repeat this process again. I'm gonna stick with 3. Now simplify the 9.

                 243

3                                     81

                                3            27

                                           3      9

                                                  3    3

For every pair of number we have that are the same we get to put one outside the sqareroot sign (I know that sounds confusing). Start by listing them like this.

3 x 3 x 3 x 3 x 3

Now organize into groups of two.

(3x3)(3x3)(3)   Notice we have two groups that are paired. This means we can take two 3's and bring them outside the squareroot sign. Like this

3x3\sqrt{3}  

9\sqrt{3}

The lone 3 just goes back in the squareroot. once you can't find a number to divide the number inside the sign by you have simplified the expression completely. Hope that makes some sense

5 0
3 years ago
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