How much simple interest does $4,678.00 earn in 529 days at a rate of 7.3%? Round to the nearest cent.

You roll two six-sided fair nukber cubes.Whatbis the probability that you will roll snake eyes(both ones)?

Katyanochek1 [597]

Answer:

1/36

Step-by-step explanation:

Each dice has a 1 in 6 chance to land on a 1, but for both dice to land on 1's it would be $(\frac{1}{6} )(\frac{1}{6})$ = $\frac{1}{36}$

3 0

3 years ago

If un=n(n2+1), evaluate u5-u4

Vesna [10]

Answer: 62
Hope this helps : )

6 0

3 years ago

Help i have no idea how to solve this

ASHA 777 [7]

Answer:

AB =24

Step-by-step explanation:

So, since all the sides are equal, you can just take two of the sides and set em equal to each other to find x and then, solve for AB

4x+8 =6x

8= 6x-4x

8=2x

8/2 =x

x= 4

Now, find AB, which is 4x+8

4(4) + 8

16+8 = 24

Hope this helps!

Please mark brainliest if you think I helped! Would really appreciate!

5 0

3 years ago

I'm not sure if D is right

Rzqust [24]

Ratio and proportion

height :legnth of shadow=56:49 (man's shadow)
we assume the ratio is the same for the tower thing (obelisk)

so
56:49=x:28
conver tto fraction
56/49=x/28
times both sides by 28
1568/49=x
32=x
answer is 32ft

5 0

3 years ago

Suppose we are testing people to see if the rate of use of seat belts has changed from a previous value of 88%. Suppose that in

Andreas93 [3]

Answer:

a) We would expect to see 500*0.88=440

b) $z=\frac{0.9 -0.88}{\sqrt{\frac{0.88(1-0.88)}{500}}}=1.376$

$p_v =2*P(Z>1.376)=0.167$

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion is not significant different from 0.9.

The p value is a criterion to decide if we reject or not the null hypothesis, when $p_v$ we reject the null hypothesis in other case we FAIL to reject the null hypothesis. And represent the "probability of obtaining the observed results of a test, assuming that the null hypothesis is correct".

Step-by-step explanation:

Data given and notation

n=500 represent the random sample taken

X=450 represent the people that have the seat belt fastened

$\hat p=\frac{450}{500}=0.9$ estimated proportion of people that have the seat belt fastened

$p_o=0.88$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v{/tex} represent the p value (variable of interest) Part aWe would expect to see 500*0.88=440Part bConcepts and formulas to use We need to conduct a hypothesis in order to test the claim that the true proportion changes fro m 0.88.: Null hypothesis:[tex]p=0.88$

Alternative hypothesis: $p \neq 0.88$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.9 -0.88}{\sqrt{\frac{0.88(1-0.88)}{500}}}=1.376$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed is $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(Z>1.376)=0.167$

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion is not significant different from 0.9.

The p value is a criterion to decide if we reject or not the null hypothesis, when $p_v$ we reject the null hypothesis in other case we FAIL to reject the null hypothesis. And represent the "probability of obtaining the observed results of a test, assuming that the null hypothesis is correct".

8 0

3 years ago