To solve this problem, you must follow the proccedure below:
1. T<span>he block was cube-shaped with side lengths of 9 inches and to calculate its volume (V1), you must apply the following formula:
V1=s</span>³
<span>
s is the side of the cube (s=9)
2. Therefore, you have:
V1=s</span>³
V1=(9 inches)³
V1=729 inches³
<span>
3. The lengths of the sides of the hole is 3 inches. Therefore, you must calculate its volume (V2) by applying the formula for calculate the volume of a rectangular prism:
V2=LxWxH
L is the length (L=3 inches).
W is the width (W=3 inches).
H is the heigth (H=9 inches).
4. Therefore, you have:
V2=(3 inches)(3 inches)(9 inches)
V2=81 inches
</span><span>
5. The amount of wood that was left after the hole was cut out, is:
</span>
Vt=V1-V2
Vt=648 inches³
Answer:
The y-intercept is (0,-3
Step-by-step explanation:
- Y=mx+b
- Y= 1.5x-4.5
- So (0,-3) is the y-intercept.
1. Count how many men are fit to climb:
200 men - 100%
x men - 12 %
Then
2. 60 are fit enough to climb Mount Shasta in California, among them 24 are men, then 60-24=36 are women.
3. The probability that a person picked at random from the group is a male is
4. The probability that a person picked at random from the group is fit to climb Mount Shasta is
5. Use formula
6.
Then
7.
Answer: 0.472 (or in percent near 47.2%).
7300-5500=1800 needs to come from salespeople. To make at least 7300, the salespeople need to make at least 1800, which means:
300 x number of people >= 1800
Number of people >= 6
C is correct
Answer:
0.97725
Step-by-step explanation:
Given that Professor Heinz has given the same multiple-choice final exam in his Principles of Microeconomics class for many years. After examining his records from the past 10 years, he finds that the scores have a mean of 76 and a standard deviation of 12.
i.e.
Std error of mean = sigma/sqrt n = 2
Thus the sample mean is N(76,2)
Required probability = probability that a class of 36 students will have an average greater than 72 on Professor Heinz's final exam.
=