Your answer is C hope that helped
<span>You need information that you haven't provided in the question. Perhaps your text has a table of ΔGof for these compounds. In that case,
ΔGorxn = Sum of ΔGof products - ΔGof reactants
Just plug in the values that you find and calculate the free energy change of the reaction</span>
Answer:
Explanation:
Remark
First of all you have to identify what is happening. You make the following observations.
The solution in the test tube in a cold water bath is colorless.
As you add heat, the color changes from colorless to brown.
What you are told
N2O4 is colorless
NO2 is brownish red.
What you conclude
The reaction is endothermic. That means it requires heat to happen. An endothermic reaction is
A + Heat ===> B
So you have three possible correct answers
N2O4 + 14 kCal ===> 2NO2
N2O4 ====> 2NO2 dH = 14 kCal
N2O4 ====> 2NO2 - 14 kCal
I can't read the last 4 equations.
Other answers
As the temperature increased, the N2O4 became less.
As the temperature increased, the products were favored. (color change)
The reaction is exothermic (gives off heat) when the reaction goes from
NO2 - Heat ===> N2O2
Explanation:
Given that,
The density of mercury is 13.5 g/mL
The density of Bromine is 3.12 g/cm³
It is mentioned that Mercury and bromine have the same mass. Let d₁,d₂ are the density of Mercury and Bromine. V₁ and V₂ are their volumes. So,
Since, mass is same.
So,
Hence, the volume of bromine is more than that of mercury. It is 4.32 times of the density of mercury.