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Answer:
a) Endothermic
b) T₂ = 53.1 ºC
Explanation:
a) We are told that when the ammonium nitrate dissolves in water the pack gets cold so the system is absorbing heat from the surroundings and by definition it is an endothermic process.
b) Recall that the heat, Q, is given by the formula:
Q = mcΔT where m is the mass of water,
c is the specific heat of water, and
ΔT is the change in temperature
We can determine the value for Q since we are given the heat of solution for the ammonium nitrate. From there we can calculate ΔT and finally answer our question.
Molar mass NH₄NO₃ = 80.04 g/mol
moles NH₄NO₃ = 50.0 g/ 80.04 g/mol = 0.62 mol
Q = 25.4 kJ/mol x 0.62 mol = 15.87 kJ = 15.87 kJ x 1000 J = 1.59 x 10⁴ J
Q = mcΔT ⇒ ΔT = Q/mc
ΔT = 1.59 x 10⁴ J/ (135 g x 4.184 J/gºC ) = 28.1 ºC
T₂- T₁ = ΔT ⇒ T₂ = ΔT + T₁ = 28.1 ºC +25.0 ºC = 53.1 ºC
Answer:
Described in the explanation section
Explanation:
Ice is the solid phase of water and this phase, the water molecules usually have very little energy and therefore can't detach from each other. This is because the water molecules are closely packed together in a regular arrangement normally called lattice.
Now, when the ice is heated to become a liquid, the energy of the water molecules increases and thus some of them will have enough energy to overcome the intermolecular forces that had been keeping them closely packed in the ice phase. This will then make the water molecules to move further apart thereby forming liquid water.
Now, when the molecules are heated further, the liquid water will now turn into water vapor, which is the gas phase of water. The molecules in this gas phase will have more energy than in the liquid phase because the average distances between each of them will be much larger than the size of the molecules themselves.
Answer:
The specific heat capacity of silver metal is 0.021485 J/g°C.
Explanation:
The specific heat capacity of silver metal can be found out by using the formula,
Q = (mass) (ΔT) (Cp)
Given,
mass = 75 grams
Q = 56.4 j
ΔT = 35°C
Substituting values,
56.4 = (75)(35)(Cp)
Cp = 0.021485 J/g°C.
I think the answer is 1s²2s²2p⁶. Since neon has an atomic number of 10, we know that it needs to have 10 electrons and since it is in the second row it cannot have any d electrons which makes the first option incorrect. The second option is incorrect because the 2s⁴ can't exist since s orbitals can only hold 2 electrons. The fourth option cannot be right because it again neon cannot have d electrons due to it being in the second row.
I hope this helps. Let me know if anything is unclear.
