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ololo11 [35]
3 years ago
5

Which is true about the dissolving process in water?

Chemistry
2 answers:
masha68 [24]3 years ago
6 0

Answer:

c

Explanation:

amid [387]3 years ago
5 0
Water molecules move througout the solute
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Consider the fructose-1,6-bisphosphatase reaction. Calculate the free energy change if the ratio of the concentrations of the pr
Lyrx [107]

Answer:

The free energy change for the reaction at 37.0°C is -8.741 kJ.

Explanation:

The free energy of the reaction is given by :

\Delta G=\Delta G^o+RT\ln K

where,

\Delta G^o = standard Gibbs free energy

R = Gas constant = 8.314J/K mol

T = temperature in Kelvins

K = equilibrium constant

We have :

\Delta G^o=-16.7 kJ/mol=-16,700 J/mol

1 kJ = 1000 J

T = 37.0 C = 37 +273.15 K = 310.15 K

Ratio of concentrations of the products to the concentrations of the reactants =K = 21.9

\Delta G=-16,700 J/mol+8.314J/K mol\times 310.15 K \ln[21.9]

=-8,741.22 J = -8.741 kJ

The free energy change for the reaction at 37.0°C is -8.741 kJ.

5 0
3 years ago
What is a characteristic of branched chained alkanes?
olga2289 [7]

C) They have more than two carbons that are bonded to only one other carbon

4 0
3 years ago
Read 2 more answers
How many atoms are found in the chemical formula below
Stolb23 [73]

Answer:

2 atoms

Explanation:

There are 2 atoms in element NaCl. This is because there is 1 atom of Na (sodium) and 1 atom of Cl (chlorine) in each NaCl molecule. Elements by themselves do not have a "number of atoms"- if you're talking about the atomic number, it's the number of protons (or electrons in a neutral atom) of an element.

6 0
3 years ago
Read 2 more answers
Which statement related to particle and wave properties of matter is correct? a. Interference patterns are observed when a wave
DerKrebs [107]

Answer:

a. Interference patterns are observed when a wave passes through a barrier with two slits

Explanation:

Interference is a situation where two waves superimpose to form a new wave of a different amplitude. This amplitude can be greater, same or lower.

the diagram attached below shows the movement of a wave through a barrier with two slits.

you can notice the portions of the wave that overlap. This overlapping of waves is the interference.

Thus, option A is correct.

The other options however,  are not correct. as shown below:

Option B is wrong as waves exhibit diffraction <em>(it is diffraction of the light wave that produces the rainbows we see in the sky)</em>

Option C is wrong as waves do not travel straight through slits always.

Option D is wrong as waves can also interfere constructively and destructively.

7 0
4 years ago
The reaction of Cr2O3 with silicon metal at high temperatures will make chromium metal. 2CrO3(s) + 3Si(s)----&gt; 4Cr(l) + 3SiO2
nalin [4]

Answer: 51.45 grams of excess reagent is left after the completion of reaction.

Explanation: For the calculation of moles, we use the formula:

Moles=\frac{\text{Given mass}}{\text{Molar mass}}     ....(1)

  • For Si

Given mass = 92 grams

Molar mass = 28g/mol

Putting values in equation 1, we get:

Moles=\frac{92g}{28g/mol}=3.285moles

  • For Cr_2O_3

Given mass = 112 grams

Molar mass = 116g/mol

Putting values in equation 1, we get:

Moles=\frac{112g}{116g/mol}=0.965moles

The reaction follows:

2Cr_2O_3(s)+3Si(s)\rightarrow 4Cr(l)+3SiO_2(s)

By Stoichiometry,

2 moles of Cr_2O_3 reacts with 3 moles of silicon

So, 0.965 moles of Cr_2O_3 reacts with = \frac{3}{2}\times 0.965 = 1.4475 moles of Silicon.

As, the moles of silicon is more than the required amount and is present in excess.

So, the excess reagent for the reaction is Silicon.

Moles of silicon remained after reaction = 3.285 - 1.4475 = 1.8375 moles

To calculate the amount of Silicon left in excess is calculated by using equation 1:

1.8375=\frac{\text{Given mass}}{28}

Amount of Silicon in excess will be 51.45 grams.

5 0
4 years ago
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