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Harman [31]
4 years ago
8

X=1.6 satisfy the equation 6-4x= - x/4

Mathematics
1 answer:
marusya05 [52]4 years ago
3 0
6-4(1.6)=-1.6/4
-0.4=-0.4
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Write the quadratic equation with the given roots 3 and -2/3
trapecia [35]

<em>Answer: </em>

<em>y  =  </em>x^{2}<em> −  7  x  3  − 2</em>

<em />

<em>Step-by-step explanation:</em>

<em>you gotta work backwards to find the factors from the roots then multiply the factors together.</em>

7 0
3 years ago
Please show ALL work<br><br> 4-5(2x+11)+6x=6-4(-x-9)-5
svp [43]

Step 1. Simplify 6 - 4(-x-9)-5 to -4(-x-9) + 1

4 - 5(2x + 11) + 6x = -4(-x-9) + 1

Step 2. Expand

4 - 10x - 55 + 6x = 4x + 36 + 1

Step 3. Simplify 4 - 10x - 55 + 6x to -51 - 4x

-51 - 4x = 4x + 36 + 1

Step 4. Simplify 4x + 36 + 1 to 4x + 37

-51 - 4x = 4x + 37

Step 5. Add 51 to both sides

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Step 6. Simplify 4x + 37 + 51 to 4x + 88

-4x = 4x + 88

Step 7. Subtract 4x from both sides

-4x - 4x = 88

Step 8. Simplify -4x - 4x to -8x

x = -88/8

Step 10. Simplify 88/8 to 11

x = -11


6 0
3 years ago
Read 2 more answers
The answers..............................
HACTEHA [7]

Answer:

DAM BROOOOO UR SCREEN.

Step-by-step explanation:

5 0
3 years ago
Help pls. not harddd. giving lots of points, give small explanation.
katrin2010 [14]

9514 1404 393

Answer:

  4

Step-by-step explanation:

The function is of even degree. You can tell this because the end behavior is the same at both ends.

There are at least 4 zeros. There are 2 zeros of multiplicity 1 and one zero of multiplicity 2.

The crossings of the x-axis at x=-2 and x=3 have no flat spot, so the multiplicity must be 1; not 3, 5, or some other odd number.

You can tell the zero at x=1 is even multiplicity, because the graph does not cross the x-axis there. You can tell the multiplicity is only 2 because the curve is not flat enough for it to be 4 or more.

A polynomial function with 4 real zeros has a minimum degree of 4.

3 0
3 years ago
How much would $200 invested at 5% interest compounded monthly be worth after 9 years? Round your answer to the nearest cent.
Allisa [31]
A = P(1 + \frac{r}{n})^{nt}
A = 200(1 + \frac{0.05}{12})^{(12)(9)}
A = 200(1 + \frac{1}{240})^{108}
A = 200(1\frac{1}{240})^{108}
A = 200(1.56684664942)
A = 313.369329884
A = \$313.37
7 0
3 years ago
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