Answer:
5/18 ÷ 4/9
Step-by-step explanation:
because 3/8 ÷ 3/5 equals to 5/8 and 5/18 ÷ 4/9 also equals to 5/8
Answer:
The GCF of both is g^3
Step-by-step explanation:
Here, we are asked to give the greatest common factor of g^3 and g^15
In simpler terms we want to find that biggest term that could divide both values.
Mathematically, since g^3 is itself a factor of g^15, then we can conclude that the GCF of both is g^3
Answer:
Step-by-step explanation:
a) <u>Jamal spent:</u>
<u>Isaiah spent:</u>
<u>The equation is:</u>
b) <u>Solving the equation</u>
- 2x = 3x - 6.75
- 3x - 2x = 6.75
- x = 6.75
c) <u>Jamal's items cost </u>
<u>Isaiah's items cost </u>
- $6.75 - $2.25 = $4.50 each
Answer:
f) a[n] = -(-2)^n +2^n
g) a[n] = (1/2)((-2)^-n +2^-n)
Step-by-step explanation:
Both of these problems are solved in the same way. The characteristic equation comes from ...
a[n] -k²·a[n-2] = 0
Using a[n] = r^n, we have ...
r^n -k²r^(n-2) = 0
r^(n-2)(r² -k²) = 0
r² -k² = 0
r = ±k
a[n] = p·(-k)^n +q·k^n . . . . . . for some constants p and q
We find p and q from the initial conditions.
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f) k² = 4, so k = 2.
a[0] = 0 = p + q
a[1] = 4 = -2p +2q
Dividing the second equation by 2 and adding the first, we have ...
2 = 2q
q = 1
p = -1
The solution is a[n] = -(-2)^n +2^n.
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g) k² = 1/4, so k = 1/2.
a[0] = 1 = p + q
a[1] = 0 = -p/2 +q/2
Multiplying the first equation by 1/2 and adding the second, we get ...
1/2 = q
p = 1 -q = 1/2
Using k = 2^-1, we can write the solution as follows.
The solution is a[n] = (1/2)((-2)^-n +2^-n).
Answer:
4,200 liters
Step-by-step explanation:
The flow rate is given by:
Integrating the flow rate expression from t=0 to t=30 minutes, yields the total volume that flows out of the tank during that period:
4,200 liters of water flow from the tank during the first 30 minutes.
