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3 years ago

15

Below are the line plots for two data sets . Find the mean of each data set

1 answer:

STALIN [3.7K]3 years ago

4 0

Sorry if this isn’t the right answer :(
A. 2 + 1 + 2 + 1 + 2 / 5 = 1.6

B. 4 + 4 + 4 + 4 / 4 = 4

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How do I do systems of Equations- Elimination method

Reptile [31]

In the elimination method you either add or subtract the equations to get an equation in one variable.

5 0

3 years ago

Solve the inequality and enter your solution as an inequality in the box below.

kvv77 [185]

Answer:

X=6

Step-by-step explanation:

add 5 on both sides then 5=1=6 so X=6

6 0

3 years ago

Ervin sells vintage cars. Every three months, he manages to sell 13 cars. Assuming he sells cars at a constant rate, what is the

Vladimir [108]

Ervin sells 13 cars per 3 months so 13/3=4.3 cars per month.

this means that

___month___ ___cars sold___

1 4.3
2 2*4.3
3 3*4.3
: :
n n*4.3

the linear function representing the cars sold per month is f(n)=4.3*n

(Practically, this means that the expected number of cars sold after n months is a whole number close to 4.3*n.)

Answer:

the slope is 4.3 (13/3)

7 0

3 years ago

A school wishes to enclose its rectangular playground using 480 meters of fencing.

Harlamova29_29 [7]

Answer:

Part a) $A(x)=(-x^2+240x)\ m^2$

Part b) The side length x that give the maximum area is 120 meters

Part c) The maximum area is 14,400 square meters

Step-by-step explanation:

The picture of the question in the attached figure

Part a) Find a function that gives the area A(x) of the playground (in square meters) in terms of x

we know that

The perimeter of the rectangular playground is given by

$P=2(L+W)$

we have

$P=480\ m\\L=x\ m$

substitute

$480=2(x+W)$

solve for W

$240=x+W\\W=(240-x)\ m$

<u><em>Find the area of the rectangular playground</em></u>

The area is given by

$A=LW$

we have

$L=x\ m\\W=(240-x)\ m$

substitute

$A=x(240-x)\\A=-x^2+240x$

Convert to function notation

$A(x)=(-x^2+240x)\ m^2$

Part b) What side length x gives the maximum area that the playground can have?

we have

$A(x)=-x^2+240x$

This function represent a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The x-coordinate of the vertex represent the length that give the maximum area that the playground can have

Convert the quadratic equation into vertex form

$A(x)=-x^2+240x$

Factor -1

$A(x)=-(x^2-240x)$

Complete the square

$A(x)=-(x^2-240x+120^2)+120^2$

$A(x)=-(x^2-240x+14,400)+14,400$

$A(x)=-(x-120)^2+14,400$

The vertex is the point (120,14,400)

therefore

The side length x that give the maximum area is 120 meters

Part c) What is the maximum area that the playground can have?

we know that

The y-coordinate of the vertex represent the maximum area

The vertex is the point (120,14,400) -----> see part b)

therefore

The maximum area is 14,400 square meters

Verify

$x=120\ m$

$W=(240-120)=120\ m$

The playground is a square

$A=120^2=14,400\ m^2$

8 0

3 years ago

Solve for c in the scientific formula C=Wtc/1000

Troyanec [42]

C = Wtc/1000

1000C = Wtc

Wtc = 1000C

W = (1000C) / (tc)

This is assuming that C and c are not the same.

If they are the same, we have:

W = (1000) / t, provided ,that C and c are not equal to 0.

3 0

2 years ago