ST has endpoints S(-2,-4) and T(6,8). Find the coordinates of the midpoint of ST.

Sebastian swam laps every day in the community swimming pool. He swam 45 minutes each day, 5 days each week, for 12 weeks. In th

lord [1]

Answer:

$\text{Average rate}=\frac{\text{40 laps}}{\text{ hour}}$

Step-by-step explanation:

Please consider the complete question.

Sebastian swan laps every day in the community swimming pool. He swam 45 minutes each day, 5 days each week, for 12 weeks. In that time, he swam 1800 laps. What was his average rate in laps per hour?

Let us convert time taken into hours as:

$\text{Days}=5\times 12=60$

$\text{Minutes}=60\times 45$

1 hour = 60 minutes. To convert minutes into hours, we will divide total minutes by 60.

$\text{Hours}=\frac{60\times 45}{60}=45$

Now, we will divide 1800 by 45 to find average rate in laps per hour as:

$\text{Average rate}=\frac{\text{1800 laps}}{\text{45 hours}}$

$\text{Average rate}=\frac{\text{40 laps}}{\text{ hour}}$

Therefore, Sebastian's average rate is 40 laps per hour.

6 0

2 years ago

Data is collected to compare two different types of batteries. We measure the time to failure of 12 batteries of each type. Batt

-Dominant- [34]

Using the t-distribution, it is found that since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

At the null hypothesis, it is tested if it does not outlast by more than 2 hours, that is, the subtraction is not more than 2:

$H_0: \mu_B - mu_A \leq 2$

At the alternative hypothesis, it is tested if it outlasts by more than 2 hours, that is:

$H_1: \mu_B - \mu_A > 2$

The sample means are: $\mu_A = 8.65, \mu_B = 11.23$

The standard deviations for the samples are $s_A = s_B = 0.67$

Hence, the standard errors are:

$s_{Ea} = S_{Eb} = \frac{0.67}{\sqrt{12}} = 0.1934$

The distribution of the difference has mean and standard deviation given by:

$\overline{x} = \mu_B - \mu_A = 11.23 - 8.65 = 2.58$

$s = \sqrt{s_{Ea}^2 + s_{Eb}^2} = \sqrt{0.1934^2 + 0.1934^2} = 0.2735$

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 2$ is the value tested at the hypothesis.

Hence:

$t = \frac{\overline{x} - \mu}{s}$

$t = \frac{2.58 - 2}{0.2735}$

$t = 2.12$

The critical value for a right-tailed test, as we are testing if the subtraction is greater than a value, with a 0.05 significance level and 12 + 12 - 2 = 22 df is given by $t^{\ast} = 1.71$

Since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

A similar problem is given at brainly.com/question/13873630

7 0

2 years ago

2(z-3) <img src="https://tex.z-dn.net/?f=2%28z%20-%203%29%20%5Cgeqslant%205" id="TexFormula1" title="2(z - 3) \geqslant 5" al

Alenkinab [10]

Answer:

2z-6

Step-by-step explanation:

2(z-3)

2(z)-2(3)=2z-6

3 0

2 years ago

Plz help!! Will give 30 points!!

Inessa [10]

Answer:

B) 12

Step-by-step explanation:

C is the circumference, d is the diameter, and r is the radius. They are related by the following equations:

d = 2r

C = πd = 2πr

If d = 6.0, then r = 3.0.

If C / C' = 0.25, then:

(2πr) / (2πr') = 0.25

r / r' = 0.25

3 / r' = 0.25

r' = 12

8 0

3 years ago

Read 2 more answers

What’s 10% of 70 I really need the answer plz help!!!!!

egoroff_w [7]

7

10% of 70 is 7

hope this help

6 0

2 years ago

Read 2 more answers