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otez555 [7]
3 years ago
10

Help me, please :) I need to find the value of x

Mathematics
1 answer:
irina1246 [14]3 years ago
3 0
The vale of x is 55 !!
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3x - y = 2 and 2x + y = 4<br> X=<br> y =
AveGali [126]

Answer:

.The solution is

x = 1.2

y = 1.6

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What is the missing angle in the right triangle?
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Answer:

68

Step-by-step explanation:

For angle A, 3 is the adjacent leg. 8 is the hypotenuse.

The trig ratio that relates the adjacent leg to the hypotenuse is the cosine.

\cos A = \dfrac{adj}{hyp}

\cos A = \dfrac{3}{8}

\cos A = 0.375

We know the cosine of angle A equals 0.375. We take the inverse cosine of 0.375 to find the measure of the angle.

A = \cos^{-1} 0.375

A = 68^\circ

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The sum of squares of two consecutive positive even integers is 52 more than their product. Find these numbers.
natulia [17]

Answer:

The first set of consecutive even integers equals (8 , 6)

The second set is ( - 8 and - 6) which also works.

Step-by-step explanation:

Equation

(x)^2 + (x + 2)^2 = (x)(x + 2) + 52            Remove the brackets on both sides

Solution

x^2 + x^2 + 4x + 4 = x^2 + 2x + 52        Collect the like terms on the left

2x^2+ 4x+ 4 = x^2 + 2x + 52                  Subtract right side from left

2x^2 - x^2 + 4x - 2x + 4 - 52  =  0          Collect the like terms

x^2 + 2x - 48 = 0                                     Factor

(x + 8)(x - 6) = 0

Answer

Try the one you know works.

x - 6 = 0

x = 6

Therefore the two integers are 6 and 8

6^2 + 8^2 = 100

6*8 + 52  = 100

So 6 and 8 is one set of  consecutive even numbers that works.    

========================

What about the other set.

x + 8 = 0

x = - 8

x and x + 2

- 8  and -8 + 2 = - 8, - 6

(- 8 )^2 + (- 6)^2 = 100

(-8)(-6) + 52 = 100

Both sets of consecutive numbers work.


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