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vazorg [7]
3 years ago
7

Geometry, please answer question ASAP

Mathematics
1 answer:
Pepsi [2]3 years ago
7 0

Answer:

Figures A,D are polygons.

Reason:

Polygon is a closed figure with atleast three strange lines and angles.

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Sue either travels by bus or walks when she visits the shops. The probability that she catches the bus from the shops is 0.7. Sh
Alina [70]

Corrected Question

Sue travels by bus or walks when she visits the shops. The probability that she catches the bus to the shops is 0.4. The probability she catches the bus from the shops is 0.7. Show the probability that Sue walks at one way is 0.72

Answer:

P(A \cup B) =0.72 (Proved)

Step-by-step explanation:

Sue travels by bus or walks when she visits the shops.

Let the event that she catches the bus to the shop=A

Let the event that she catches the bus from the shop=B

P(A)=0.4

P(B)=0.7

Both A and B are independent events.

Therefore,Probability that she catches the bus to and from the shop:

P(A∩B) = 0.4 X 0.7= 0.28

Probability Sue walks at least one way P(A \cup B) = 1 - P(A \cap B)

= 1 - 0.28\\= 0.72

Hence, the probability that Sue walks at least one way is 0.72.

8 0
3 years ago
PLS HELP Find the m∠RLU.<br> A. 10º<br> B. 6º<br> C. 25º<br> D. 50º
balandron [24]

Step-by-step explanation:

6n-10=50

6n=60

n=10

rlu=6n-10

=6×10-10

=60-10

50

8 0
3 years ago
5. Lisa sold costume jewelry at a bazaar. The
julsineya [31]

Answer:

$4

Step-by-step explanation:

2 Bracelets + 3 rings = $26

2 rings = $12

3 rings = x

To get the cost of 1 ring you divide 12 by 2 and the answer you get is 6.

The total cost of the 3 rings is $18( $6*3)

Then you subtract the cost of both 2 bracelets and 3 rings($26) from the cost of 3 rings($18). The answer is $8. ( THIS IS THE COST OF 2 BRACELETS)

<u>1 BRACELET= $4( $8/2)</u>

8 0
3 years ago
How is 1.35 x 10–5 written in standard notation?
natka813 [3]

Answer:

13.5x - 5

Step-by-step explanation:

8 0
3 years ago
Proving That All Circles Are Similar
Nitella [24]

Answer:

Figures can be proven similar if one, or more, similarity transformations (reflections, translations, rotations, dilations) can be found that map one figure onto another. In our attempt to prove all circles are similar, a translation and a scale factor (from a dilation) will be found to map one circle onto another.

Step-by-step explanation:

4 0
3 years ago
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