3 years ago

PLS HELP ME I HAVE ONLY 10 MINS

Mathematics

1 answer:

anastassius [24]3 years ago

8 0

Sorry habibti it’s okay tho f school

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Help in the triangle QUESTION plz :'(

scoundrel [369]

I'm pretty sure it's 3

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4 years ago

PLEASE HELP ME ASAP

goblinko [34]

Answer:

20.04 units

Step-by-step explanation:

The diagram shows right triangle ABC. Use the definition of the cosine:

$\cos \angle C=\dfrac{\text{Adjacent leg}}{\text{Hypotenuse}}\\ \\\cos \angle C=\dfrac{BC}{AC}\\ \\\cos 51^{\circ}=\dfrac{BC}{27}\\ \\BC=27\cdot \cos 51^{\circ}\\ \\BC\approx 20.04\ units$

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4 years ago

What is 3/tan(30°) in radical form? (meant to be a fraction)

Kitty [74]

$\bf y=\cfrac{3}{tan(30^o)}\implies y=\cfrac{3}{\frac{sin(30^o)}{cos(30^o)}}\implies y=\cfrac{3}{\frac{\quad \frac{1}{2}\quad}{\frac{\sqrt{3}}{2}} }\implies y=\cfrac{3}{\frac{1}{2}\cdot \frac{2}{\sqrt{3}}}
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y=\cfrac{3}{\quad \frac{1}{\sqrt{3}}\quad }\implies y=\cfrac{3}{1}\cdot \cfrac{\sqrt{3}}{1}\implies y=3\sqrt{3}$

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3 years ago

PLEASE HELP FIND THE SLOPE OF THE LINE PLEASEEE!!!!!

pochemuha

2/1 the slope = rise/run

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3 years ago

The length of the famed fred's fence is 5 more than twice it's width if the perimeter of the fence is 510 feet find the dimensio

Sveta_85 [38]

Answer:

83 1/3 ft wide
171 2/3 ft long

Step-by-step explanation:

Let w represent the width of the area. Then 2w+5 represents the length. The perimeter is twice the sum of length and width:

P = 2(L+W)

510 = 2(2w+5 +w) . . substitute given values

255 = 3w +5 . . . . . . divide by 2

250 = 3w . . . . . . . . . subtract 5

83 1/3 = w . . . . . . . . .divide by 3; the width of the area

2w+5 = 171 2/3 . . . . the length of the area

The fenced area is 83 1/3 ft wide and 171 2/3 ft long.

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4 years ago