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tester [92]
2 years ago
10

PLS HELP ME I HAVE ONLY 10 MINS

Mathematics
1 answer:
anastassius [24]2 years ago
8 0
Sorry habibti it’s okay tho f school
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I NEED HELP ASAP PLZZZZ
KonstantinChe [14]

Step-by-step explanation:

We just subsitue 3 for x and -4 for y, so we get

3(3) - 5( - 4) = 9 + 20 = 29

So

a = 29

7(3) + ( - 4) = b

21 - 4 = 17

b = 17

7 0
2 years ago
Two points on L1 and two points on L2 are given. Use the slope formula to determine if lines L1 and L2 are parallel, perpendicul
vlada-n [284]

Answer:

The lines L1 and L2 neither parallel nor perpendicular

Step-by-step explanation:

* Lets revise how to find a slope of a line

- If a line passes through points (x1 , y1) and (x2 , y2), then the slope

 of the line is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- Parallel lines have same slopes

- Perpendicular lines have additive, multiplicative slopes

 ( the product of their slopes is -1)

* Lets solve the problem

∵ L1 passes through the point (1 , 10) and (-1 , 7)

- Let (1 , 10) is (x1 , y1) and (-1 , 7) is (x2 , y2)

∴ x1 = 1 , x2 = -1 and y1 = 10 , y2 = 7

∴ The slope of L1 is m1 = \frac{7-10}{-1-1}=\frac{-3}{-2}=\frac{3}{2}

∵ L2 passes through the point (0 , 3) and (1 , 5)

- Let (0 , 3) is (x1 , y1) and (1 , 5) is (x2 , y2)

∴ x1 = 0 , x2 = 1 and y1 = 3 , y2 = 5

∴ The slope of L2 is m2=\frac{5-3}{1-0}=\frac{2}{1}=2

∵ m1 = 3/2 and m2 = 2

- The two lines have different slopes and their product not equal -1

∴ The lines L1 and L2 neither parallel nor perpendicular

7 0
2 years ago
3x-5y= -25<br> Solve for x
UkoKoshka [18]
Your answer will x= 5y/3-25/3

7 0
3 years ago
Please Help I'm in need for help
Mama L [17]
I hope this helps you

5 0
3 years ago
The product of 7/16, 4/3, and 1/2 is
Eva8 [605]
First, we have two multiply two fractions (7/16 x 4/3) which we do top x top and bottom x bottom which gives us 28/48 

Second, we do 28/48 x 1/2 which is 28/96.

Lastly, we simplify 28/96 which gives us 7/24
4 0
3 years ago
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