Answer: Choice D
9, 30, 93, 282, 849
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Explanation:
The notation
tells us that the first term is 9
The notation
says that we multiply the (n-1)st term by 3, then add on 3 to get the nth term ![a_n](https://tex.z-dn.net/?f=a_n)
So if we wanted the second term for instance, then we'd say
![a_n = 3*(a_{n-1})+3\\\\a_2 = 3*(a_{2-1})+3\\\\a_2 = 3*(a_{1})+3\\\\a_2 = 3*(9)+3\\\\a_2 = 27+3\\\\a_2 = 30\\\\](https://tex.z-dn.net/?f=a_n%20%3D%203%2A%28a_%7Bn-1%7D%29%2B3%5C%5C%5C%5Ca_2%20%3D%203%2A%28a_%7B2-1%7D%29%2B3%5C%5C%5C%5Ca_2%20%3D%203%2A%28a_%7B1%7D%29%2B3%5C%5C%5C%5Ca_2%20%3D%203%2A%289%29%2B3%5C%5C%5C%5Ca_2%20%3D%2027%2B3%5C%5C%5C%5Ca_2%20%3D%2030%5C%5C%5C%5C)
If we want the third term, then,
![a_n = 3*(a_{n-1})+3\\\\a_3 = 3*(a_{3-1})+3\\\\a_3 = 3*(a_{2})+3\\\\a_3 = 3*(30)+3\\\\a_3 = 90+3\\\\a_3 = 93\\\\](https://tex.z-dn.net/?f=a_n%20%3D%203%2A%28a_%7Bn-1%7D%29%2B3%5C%5C%5C%5Ca_3%20%3D%203%2A%28a_%7B3-1%7D%29%2B3%5C%5C%5C%5Ca_3%20%3D%203%2A%28a_%7B2%7D%29%2B3%5C%5C%5C%5Ca_3%20%3D%203%2A%2830%29%2B3%5C%5C%5C%5Ca_3%20%3D%2090%2B3%5C%5C%5C%5Ca_3%20%3D%2093%5C%5C%5C%5C)
and so on.
The terms so far are: 9, 30, 93
You should find the fourth and fifth terms are 282 and 849 respectively if you keep this pattern going.
Therefore, the answer is choice D