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victus00 [196]
3 years ago
14

If f(x) = 1/9x-2, what is f^-1(x)?

Mathematics
1 answer:
borishaifa [10]3 years ago
5 0

Answer: i think its   f-1(x)=9x-18

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Which unit rate is equivalent to 14 miles per gallon?
Tcecarenko [31]

It would be 42 miles over 3 gallons

42/3=14

Hope this helps :)

6 0
3 years ago
Of the dogs 1/12 were classified as belonging to hound group.of the dogs in hound groups3 /10 were english foxhounds what fracti
andre [41]
So 1/12 of all dogs are in hound
of the hound gropu, 3/10 is english foxhounds
find what fraciton of all adogs are english foxhounds
so 3/10 of 1/12
in math 'of' means multiply with fractions so
3/10 times 1/12=(3 times 1)/(10 times 12)=3/120=1/40
1/40 of the dogs were english foxhounds
3 0
3 years ago
What is the common difference in the arithmic sequence 30,27,24,21,18
vichka [17]
If you have two terms in a sequence, then a term decreased by the previous term=common difference

so
30 and 27

27 decreased by 30 is -3

the common differce is -3
6 0
2 years ago
Can someone explain how to solve this I'm really confused <br><br> 1/2 to the power of 3
OleMash [197]

Answer:

1/8

Step-by-step explanation:

1/2 cubed is just 1/2*1/2*1/2 which is 1/8

5 0
3 years ago
Read 2 more answers
Two mechanics worked on a car. The first mechanic worked for 10 hours, and the second mechanic worked for 5 hours. Together they
inysia [295]
You have two unknown rates, so we need to develop two equations to solve for these unknowns (based on the information given on the problem statement):

5x + 10y = 725
x + y = 100

By substitution, we get:

5x + 10(100 - x) = 725
5x + 1000 - 10x = 725
-5x = 725 - 1000
-5x = -275
x = -275/-5 = 55

100 - 55 = 45

Thus:
The mechanic who worked for 5 hours charged his time at $55/hr, and the mechanic who worked for 10 hours charged his time at $45/hr.

To verify, plug and chug the results back into the original equations:

5(55) + 10(45) = 725
275 + 450 = 725
725 = 725 [OK]

55 + 45 = 100 [OK]
4 0
3 years ago
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