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vazorg [7]
2 years ago
13

The man with short eyelashes in Generation II marries a woman with long eyelashes. This woman reports that everyone in her famil

y also has long eyelashes. Can the man and woman be sure that all of their children will have long eyelashes? Explain.​

Biology
1 answer:
STatiana [176]2 years ago
6 0
No, they cannot be sure because the man has short eyelashes so the children each get characteristics from each parents so some may have long eyelashes and some may have short eyelashes.
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This simulation shows only the changes in energy that cause the motion of the skateboarder what energy transformations are going
Nookie1986 [14]

Answer:

Plato Answer

Explanation:

Some of the skateboarder’s stored chemical energy is being used to fuel muscle movement. This movement would also involve a release of thermal energy by the skateboarder.

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3 years ago
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7. Pyrethrums are chemicals used to kill insects. In bed bugs, the mutant-type allele, r, confers resistance, but only in homozy
natita [175]

Answer:

Allele frequency

Normal allele  = 0.9

Mutant r allele = 0.1

Genotype frequency

Homozygous normal bugs = 0.81

Homozygous mutant bug = 0.01

Heterozygous normal bug with one mutant r allele and one normal allele = 0.18

Explanation:

It is given that 99% of the bugs were killed after the spray of  pyrethrum. This suggests that 1% of the bugs that were not killed must be homozygous for the mutant type allele "r"

Thus, the frequency of homozygous "rr" species i.e q^2 = 0.01

From this we can evaluate the frequency of mutant "r" allele.

Thus, q = \sqrt{0.01} \\

q = 0.1

As per Hardy-Weinberg first equilibrium equation, p + q = 1

Substituting the value of q in above equation, we get

p = 1 - q\\p = 1 - 0.1\\p = 0.9

Thus, the frequency of homozygous normal bug is equal to

p^2 = 0.9^2 = 0.81

As per Hardy-Weinberg second equilibrium equation-

p^2 + q^2 + 2pq = 1\\

Substituting all the available values we get -

0.81 + 0.01+ 2pq = 1\\2pq = 0.18

Allele frequency

Normal allele  = 0.9

Mutant r allele = 0.1

Genotype frequency

Homozygous normal bugs = 0.81

Homozygous mutant bug = 0.01

Heterozygous normal bug with one mutant r allele and one normal allele = 0.18

3 0
3 years ago
A treatment for ingrown nails is to remove the nail and apply a chemical such as phenol to the cells of the nail mattix, which k
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Answer:

Injection of phenol to the matrix prevents regrowth of the nail causing the severe ingrown nail.

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Matrix phenolisation, also known as partial matrixectomy, involves applying <u>88% liquefied phenol</u> (distilled water as solvent) to the lateral matrix after removing the altered nail segment. Concentrated phenol is known to  have <u>antiseptic and escharotic</u> activities. It prevents regeneration of the matrix by denaturing of its contents and soft tissue proteins.

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