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Oksanka [162]
3 years ago
7

Simplify by adding like terms 3xy+2m+9-xy+3m-4​

Mathematics
2 answers:
Artyom0805 [142]3 years ago
4 0

Answer:

Step-by-step explanation:

3xy +2m +9 -xy +3m -4

add and subtract like terms

=3xy-xy+2m+3m+9-4

=2xy+5m+5

Sliva [168]3 years ago
3 0

Answer:

2xy+5m+5

Step-by-step explanation:

3xy+2m+9-xy+3m-4=(3xy-xy)+(2m+3m)+(9-4) =2xy+5m+5

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Segment EG is equal to 19
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3 years ago
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Please help and thank you!
Lynna [10]

Since polar coordinates are made up in this way

(r, \theta )

we need to solve for r and then find the angle. In our rectangular coordinate given,

(-4,-4\sqrt{3})

x = -4 and y=-4\sqrt{3}

We will use this fact to first find the angle then r, which might seem backwards but I am going to do it in this order. The formula to find the angle measure uses the tangent identity

tan\theta=\frac{y}{x}.

Filling in our y and x from the rectangular coordinate we have

tan\theta=\frac{-4\sqrt{3}}{-4} or

tan\theta =\frac{\sqrt{3}}{1}.

The tangent identity is the side opposite the reference angle (theta) over the side adjacent to it. Since in our rectangular coordinate both x and y are negative, we will be in QIII where x and y are negative. The side across from the reference angle is the square root of 3, which should tell us at this point in our math careers that the reference angle is a 60 degree angle. But in the third quadrant, the angle is 180+60 which is 240 degrees. Converting that to radians we get \frac{4\pi}{3}. That's our angle. In order to solve for r now, we will need the cosine of that angle. In our 30-60-90 right triangle we can solve for the length of the missing side which is the hypotenuse. If our Pythagorean triple is

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6 0
3 years ago
How many solutions does this linear system have? y = y equals StartFraction 2 over 3 EndFraction x plus 2. X 2 6x – 4y = –10 one
nordsb [41]

The system of equations provides a unique solution(one solution) at (-0.6, 1.6).

<h2>Given to us,</h2>
  1. y=\dfrac{2}{3}x+2
  2. 6x-4y=-10

<h3>Equation 2</h3>

As we already have the value of y from equation 1, substitute its value in equation 2,

6x-4y=-10

6x-4(\dfrac{2}{3}x+2)=-10

6x-\dfrac{8}{3}x-8=-10

\dfrac{6x}{1}-\dfrac{8}{3}x=-10+8

\dfrac{6x\times 3}{1\times 3}-\dfrac{8}{3}x=-2

\dfrac{18x-8x}{3}=-2

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x=\dfrac{-6}{10} \\\\x=-0.6

<h3>Equation 1,</h3>

y=\dfrac{2}{3}x+2

substitute the value of x in equation 1,

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Learn more about the system of equations:

brainly.com/question/12895249

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23/7 as a mixed number?
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4 years ago
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